c - FOR 循环 : Finding value of pi using a series

c - FOR 循环 : Finding value of pi using a series - absurd output

转载作者：太空宇宙更新时间：2023-11-04 08:30:01

<分区>

问题:使用以下系列求 pi 的值:pi = 4 – 4/3 + 4/5 – 4/7 + ... + ((-1)^(n-1)) 4/(2n+1) + ...

我的代码是:

#include<stdio.h>
#include<math.h>
int main () {

int n,i;
float pi;

printf("Enter number of terms : \n");
scanf("%d",&n);
pi = 0 ; 
for(i=1 ; i<n ; i++) {

    if (i%2==0)
         pi = pi + (4/(2*i)+1);
    else
         pi = pi - (4/(2*i)+1);



}

printf("value of pi is %f \n",pi);



return 0;
}