python - 递增列表索引 if 条件

Question

在遍历列表中的所有元素时，我想在遇到特定元素时跳过后面的两个元素，例如:

l1 = ["a", "b", "c", "d", "e", "f"]
for index, element in enumerate(l1):
    if element == "b":
        index = index + 2
    else:
        print(index, element)

0 a
2 c
3 d
4 e
5 f

Answer 1

更改索引不会起作用，因为它是由枚举迭代器创建的。您可以自己在迭代器上调用 next():

l1 = ["a", "b", "c", "d", "e", "f"]

iter  = enumerate(l1)
for index, element in iter:
    if element == "b":
        next(iter, None) # None avoids error if b is at the end
    else:
        print(index, element)

0 a
3 d
4 e
5 f