python - 一个术语出现在多少个列表中

Question

我有 X 个列表，例如:

[potato, pie]
[chicken,chicken,pie,donkey,potato,potato]

我想检查一个词出现在多少个列表中:

例如:

对于上面的两个列表，我希望输出是:

(potato,2)
(pie,2)
(chicken,1) - chicken is only one because it appears only in list two, not in list one.
(donkey,1)

我的尝试，但我做的完全错误并且感到困惑，如果我什至采取了正确的方法:

x = ['potato', 'pie']
z = ['chicken','chicken','pie','donkey','potato','potato']
list_final = x + z

dict_final = {}

for item in list_final:
    if item in dict_final.keys():
        dict_final.update({item:(dict_final.get(item) + 1)})
    else:
        dict_final.update({item:1})


print(dict_final)

我试过了，但这只计算它出现在列表中的所有次数:

{'potato': 3, 'pie': 2, 'chicken': 2, 'donkey': 1}

但我想得到:

{'potato': 2, 'pie': 2, 'chicken': 1, 'donkey': 1}

Answer 1

如果你让它更实用)

from collections import Counter
from functools import reduce

x = ['potato', 'pie']
y = ['chicken','chicken','pie','donkey','potato','potato']
all_lists = [x, y]
dict(Counter(reduce(lambda x, y: x + list(set(y)), all_lists, [])).most_common())
# {'potato': 2, 'pie': 2, 'donkey': 1, 'chicken': 1}