java - JSF/ICEfaces 动态层次结构树示例

Question

我有部门列表，每个部门可能有父级或没有，部门域对象如下:

- departmentId
- parentDepartmentId (null if current department has no parent i,e should be under root directly, and have value if current department have parent).
.
.
.

查看用于创建基本树的icefaces教程代码:

// create root node with its children expanded
    DefaultMutableTreeNode rootTreeNode = new DefaultMutableTreeNode();
    IceUserObject rootObject = new IceUserObject(rootTreeNode);
    rootObject.setText("Root Node");
    rootObject.setExpanded(true);
    rootTreeNode.setUserObject(rootObject);

    // model is accessed by by the ice:tree component via a getter method, this object is what's needed in the view to display the tree
    model = new DefaultTreeModel(rootTreeNode);

    // add some child nodes
    for (int i = 0; i <3; i++) {
        DefaultMutableTreeNode branchNode = new DefaultMutableTreeNode();
        IceUserObject branchObject = new IceUserObject(branchNode);
        branchObject.setText("node-" + i);
        branchNode.setUserObject(branchObject);
        rootTreeNode.add(branchNode);
    }

这都是关于构建基本节点并添加子节点。

我的情况很复杂，根下的子A可能有子节点B、C、D和D，例如子节点等等。

所以我正在考虑如何完成类似事情的最佳实践，我需要示例代码或提示(如果有人可以提供帮助)。

Answer 1

您需要一种递归方法来从模型构建树。

public void buildRecursiveTreeNode(DefaultMutableTreeNode parentTreeNode,
            String treeId, String treeName, GenericTreeVo modelVo) 
    {
            // if the database model contains more children. 
            // add the current nodes first and pass in this nodes tree id and name to construct the children for this parent nodes.


    }

更新了答案以包括递归示例。

http://www.danzig.us/java_class/recursion.html

刚刚添加了一个递归链接，我想说的是，当您从数据库迭代数据时，您会看到是否有任何子记录，如果您有子记录，您将通过传递 DefaultMutableTreeNode 来调用相同的方法，它将成为父记录。