python - 如何返回包含数字和字母的字符串中的最大整数？

Question

对于这道题，我想返回与其他整数和字符串混合时最大的整数。当我测试我的代码时，我得到的答案是 319，而不是 51。谁能帮我解决这个问题？

测试用例:

>>>biggestBuried('abcd51kkk3kk19ghi')
319


def biggestBuried(s):
    new_string = ''
    biggest = 0
    for num in s:
        if num >= '0' and num <= '9':
            new_string += num
        else:
            if not(num >= '0') and not(num <= '9'):
                return 0
            if new_string and int(new_string) > biggest:
                biggest = int(new_string)
                new_string = ''
                if new_string and int(new_string) > biggest:
                    biggest = int(new_string)
    return biggest

Answer 1

您的循环的问题在于，您仅在找到更大的数字时才设置 new_string = ''。每当您到达数字的末尾时，您都需要将其清空，即使它并不更大。

此外，当你到达结尾时，你需要检查 new_string 是否更大，以防字符串以数字结尾。我认为您正试图这样做，但缩进是错误的——它需要在 for 循环之外。

def biggestBuried(s):
    new_string = ''
    biggest = 0
    for num in s:
        if num.isnumeric():
            new_string += num
        else: # We're at the end of a number
            if new_string and int(new_string) > biggest: # Check if it's a bigger number
                biggest = int(new_string)
            new_string = '' # Start a new number
    if new_string and int(new_string) > biggest: # Check if the final number is biggest
        biggest = int(new_string)

    return biggest