gpt4 book ai didi

Python SQL - 两个左连接

转载 作者:太空宇宙 更新时间:2023-11-04 08:23:50 26 4
gpt4 key购买 nike

我在 Python 的 SQL 方面遇到了一些问题,我希望你能帮助我 - 我正在尝试从 wordpress/woocommerce 检索一些数据。

我的代码:

    cursor.execute("
SELECT t1.ID, t1.post_date, t2.meta_value AS first_name, t3.meta_value AS last_name
FROM test_posts t1
LEFT JOIN test_postmeta t2
ON t1.ID = t2.post_id
WHERE t2.meta_key = '_billing_first_name' and t2.post_id = t1.ID
LEFT JOIN test_postmeta t3
ON t1.ID = t3.post_id
WHERE t3.meta_key = '_billing_last_name' and t3.post_id = t1.ID
GROUP BY t1.ID
ORDER BY t1.post_date DESC LIMIT 20")

我收到以下错误:

    mysql.connector.errors.ProgrammingError: 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN test_postmeta t3 ON t1.ID = t3.post_id WHERE t3.meta_key = '_billing' at line 1

我做错了什么?

提前致谢。

最佳答案

在 GROUP BY 之前应该只有 1 个 WHERE 子句。
但是由于您使用 LEFT 联接,在 right 表上设置一个条件,例如 t2.meta_key = '_billing_first_name',您得到的是 INNER 联接,因为您拒绝了不匹配的行。
所以在 ON 子句中设置所有条件:

cursor.execute("
SELECT t1.ID, t1.post_date, t2.meta_value AS first_name, t3.meta_value AS last_name
FROM test_posts t1
LEFT JOIN test_postmeta t2
ON t1.ID = t2.post_id AND t2.meta_key = '_billing_first_name'
LEFT JOIN test_postmeta t3
ON t1.ID = t3.post_id AND t3.meta_key = '_billing_last_name'
GROUP BY t1.ID
ORDER BY t1.post_date DESC LIMIT 20")

尽管此查询对于 MySql 在语法上可能是正确的,但使用 GROUP BY 没有意义,因为您没有进行任何聚合。

关于Python SQL - 两个左连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59147542/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com