c - 传递二维结构数组

Question

我在传递二维结构数组时遇到困难。二维数组的大小是动态的(取决于给定的输入参数)。我收到错误:

maze_array.c:76:14: error: incompatible types when assigning to type ‘BlockNode {aka struct BlockNode}’ from type ‘BlockNode * {aka struct BlockNode *}’ Maze[i][j]=myBlockNode;

这是我的代码:

int main(int argc, char *argv[]){   

    int MazeWidth=1;
    int MazeHeight=1;
    int NumOfAvatars=1;
    BlockNode* Maze[MazeWidth][MazeHeight];
    InitializeArray(Maze[0],MazeWidth,MazeHeight,NumOfAvatars);
    return 1;
}

int InitializeArray(BlockNode** Maze,int MazeWidth, int MazeHeight, int    NumOfAvatars){

for (int i=0; i<MazeWidth;i++)
{
    for (int j=0; j<MazeHeight;j++)
    {
        //Initialize a BlockNode
        printf("HERE1\n");
        BlockNode *myBlockNode;
        myBlockNode=calloc(1,sizeof(BlockNode));
        myBlockNode->North=0;
        myBlockNode->South=0;
        myBlockNode->East=0;
        myBlockNode->West=0;
        int myArray[NumOfAvatars];
        memset(myArray,0,sizeof(myArray));
        memcpy(myBlockNode->AvatarVisited,myArray,sizeof(myArray));

        //Place BlockNode in the Maze
        Maze[i][j]=myBlockNode;
    }
}
/*
printf("North %d\n", Maze[0][0]->North);
printf("AvatarVisted %d\n", Maze[0][0]->AvatarVisited[0]);
*/


return 1;

}

Answer 1

您应该考虑到二维数组不等于指向指针的指针，例如，如果您尝试编译...

int array[10][10];
int** p=array;

...你会得到类似的错误。

如果您想传递一个二维指针数组并像AnArray[i][j] = something那样使用它，您应该将函数声明更改为...

int InitializeArray( BlockNode* Maze[][MazeHeight]
                   , int MazeWidth
                   , int MazeHeight
                   , int NumOfAvatars )

……或者……

int InitializeArray( BlockNode* (*Maze)[MazeHeight]
                   , int MazeWidth
                   , int MazeHeight
                   , int NumOfAvatars )

...并称它为...

InitializeArray( Maze
               , MazeWidth
               , MazeHeight
               , NumOfAvatars );

另请阅读 this .