Java-XPath 生成父子结构

Question

以下是 XML 结构 -

<Projects>
   <Project>
     <Name>Web Site Designing</Name>
     <Members>
        <MName>Jack</MName>
        <MName>John</MName>
        <MName>Jill</MName>
     </Members>
   </Project>
   <Project>
     <Name>Site Ranking</Name>
     <Members>
        <MName>Jack</MName>
        <MName>James</MName>
     </Members>
   </Project>
   <Project>
     <Name>E-Mailing</Name>
     <Members>
        <MName>Matt</MName>
     </Members>
   </Project>
<Projects>

在 Java 中获取以下输出的 XPath 查询是什么 -

Web Site Designing,Jack,John,Jill
Site Ranking,Jack,James
E-Mailing,Matt

现在我使用的 Java 代码没有做同样的事情。请找到下面的java代码-

.......
.......
.......
String pName = "";
String mName = "";
Document doc = builder.parse("Project.xml");
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("//Projects/Project");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
BufferedWriter out = new BufferedWriter(new FileWriter("projInfo.txt"));
Node node;
for (int i = 0; i < nodes.getLength(); i++) 
{
    node = nodes.item(i);
    pName = xpath.evaluate("Name",node);
    mName = xpath.evaluate("Members/MName",node);

    //Here's something worng
    out.write(pName + "," + mName + "\r\n");
}
out.close();
.......    

祝你有美好的一天，JB

Answer 1

mName = xpath.evaluate("Members/MName",node);

这将返回一个节点列表，但在下一个代码行中:

out.write(pName + "," + mName + "\r\n"); 

您将其视为单个字符串。

通过 mName 迭代处理 mName 中包含的所有节点是正确的。