c - 根据您的索引从 C 中的链表中删除

Question

到目前为止，我已经设法删除了第 i 个索引中的所有内容，但我需要能够将第 i 个之前的节点连接到第 i 个索引之后的节点，这是我目前所拥有的。

LinklistNode* remove_node(LinklistNode* list_head, int index){
if(list_head != NULL){
    LinklistNode* temp;
    if(list_head-> next ==NULL){
        temp = list_head;
        list_head = NULL;
    }
    else{
        LinklistNode* list_pointer = list_head;
        LinklistNode* next_list_pointer = list_pointer->next;
        while(next_list_pointer->next != NULL && index > 0){
            index--;
            list_pointer = next_list_pointer;
            next_list_pointer = next_list_pointer->next;
        }
        temp = next_list_pointer;
        list_pointer->next = NULL;
    }
    free(temp);
   }
   return list_head;
}

Answer 1

要链接索引前后的节点，将list_pointer->next指向next_list_pointer->next

while(next_list_pointer->next != NULL){
        index--;
        if (index == 0) break;
        list_pointer = next_list_pointer;
        next_list_pointer = next_list_pointer->next;
}
temp = next_list_pointer;
list_pointer->next = temp->next;