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java - 为什么我的程序不能将信息写入文件?

转载 作者:太空宇宙 更新时间:2023-11-04 08:18:15 26 4
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我必须创建一个程序,从两个已经按字母顺序排列的文件中读取姓名和 ID 号,并将它们完全按字母顺序组合到第三个文件中。文件的组织方式如下...

姓、名ID(例如 rbb091020)姓氏、名字身份证号

出于某种原因,我的文件读取了这两个文件并创建了第三个文件,但它没有向第三个文件写入任何内容。

这是我的代码...

import java.io.*;
import java.util.Scanner;

public class Combine_Files
{
public static void main(String[]args) throws IOException
{
String filename1 = "";
String filename2 = "";
String combinedFileName = "";
String response = "";
String nextName1 = "";
String nextName2 = "";
String nextIDNumber1 = "";
String nextIDNumber2 = "";
boolean okToOverwrite = false;
Scanner keyboard = new Scanner(System.in);

System.out.println("What is the name of the first file?");
filename1 = keyboard.nextLine();

File file1 = new File(filename1);

if (!file1.exists())
{
System.out.println(file1 + " does not exist.\nTerminating Program.");
System.exit(0);
}

System.out.println("What is the name of the second file?");
filename2 = keyboard.nextLine();

File file2 = new File (filename2);
if (!file2.exists())
{
System.out.println(file2 + " does not exist.\nTerminating Program.");
System.exit(0);
}

System.out.println("What is the name of the file that you wish to create?");
combinedFileName = keyboard.nextLine();
File combinedFile = new File (combinedFileName);

while (combinedFile.exists() && !okToOverwrite)
{
System.out.println("\nError, a file named " +
combinedFileName + " already exists." +
"\nWould you like to overwrite this file?" +
"\nEnter Y for Yes or N for No.");
response = keyboard.nextLine();

// Add input validation on response

if (response.equalsIgnoreCase("Y"))
{
okToOverwrite = true;
}
else
{
System.out.println("Enter a new filename.");
combinedFileName = keyboard.nextLine();
combinedFile = new File(combinedFileName);
}
}

if (file1.exists() && file2.exists())
{

Scanner list1 = new Scanner(file1);
Scanner list2 = new Scanner(file2);
PrintWriter outputFile = new PrintWriter(combinedFile);

while (list1.hasNext() && list2.hasNext())
{
nextName1 = list1.nextLine();
nextName2 = list2.nextLine();

if(nextName1.compareToIgnoreCase(nextName2) <0)
{
outputFile.print(nextName1);
nextName1 = list1.nextLine();
outputFile.print(nextName1);
}
else if(nextName1.compareToIgnoreCase(nextName2) >0)
{
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
else
{
outputFile.println(nextName1);
nextName1 = list1.nextLine();
outputFile.println(nextName1);
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
}

while (list1.hasNext() && !list2.hasNext())
{
outputFile.println(nextName1);
}

while (list2.hasNext() && !list1.hasNext())
{
outputFile.println(nextName2);
}
}
}
}

最佳答案

当您使用像 PrintWriter 这样的编写器类时,您需要确保每次想要将某些内容打印到 STDOUT 或文件时都调用 flush() 方法。因此,基本上每当您调用任何写入内部缓冲区的 PrintWriter 打印方法时,对 flush() 的调用都会将缓冲区发送到适当的输出流。

        while (list1.hasNext() && list2.hasNext())
{
nextName1 = list1.nextLine();
nextName2 = list2.nextLine();

if(nextName1.compareToIgnoreCase(nextName2) <0)
{
outputFile.print(nextName1);
nextName1 = list1.nextLine();
outputFile.print(nextName1);
}
else if(nextName1.compareToIgnoreCase(nextName2) >0)
{
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
else
{
outputFile.println(nextName1);
nextName1 = list1.nextLine();
outputFile.println(nextName1);
outputFile.println(nextName2);
nextName2 = list2.nextLine();
outputFile.println(nextName2);
}
outputFile.flush(); // <--- flush added here
}

while (list1.hasNext() && !list2.hasNext())
{
outputFile.println(nextName1);
outputFile.flush(); // <--- flush added here
}

while (list2.hasNext() && !list1.hasNext())
{
outputFile.println(nextName2);
outputFile.flush(); // <--- flush added here
}

这些对 flush() 的调用应该写入文件。

关于java - 为什么我的程序不能将信息写入文件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10056556/

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