python - 计算由空格分隔的未指定数量的整数并使用字典查找 python 中每个数字的出现次数

Question

示例输出

Enter numbers separated by spaces :1 2 3 3 2 2 2 1 3 4 5 3{'1': 2, '3': 4, '2': 4, '5': 1, '4': 1}1 occurs 2 times3 occurs 4 times2 occurs 4 times5 occurs one time4 occurs one time

So I'm a total newbie at python but I was thinking of starting off like this :

d = {}     
user = input("Enter numbers separated by spaces :") 
data = user.split() 

除了我尝试过的每个循环都一直说我不能将 str() 转换为 int()，如果有任何帮助，我将不胜感激，我已经盯着这个问题看了几个小时了..这是我尝试过的输入是字符串，试图为字典实现类似的东西

def countdigits (aString):  
  c = 10 * [0]

  for e in aString: 
    c[int(e)] += 1 

  return c 

def main (): 
  n = 0 

  for v in (countdigits(str(input('Enter a string: ')))): 
    if v == 1: 
      print(n, "occurs 1 time")
    elif v!=0:
      print(n, "occurs", v, "times")

    n += 1 

main()

对于给定的输出(但使用字典)，我想要一个类似的解决方案

Answer 1

尝试

d = {i:data.count(i) for i in data}

for k,v in d:
    print "{0} occurs {1} times\n".format(k,v)

或喜欢以下评论中的示例:

import collections

for a,b in collections.Counter(data).items():
    print "{0} occurs {1} times\n".format(a,b)