python - splinter 范围/镜头使用

Question

假设函数内被调用的函数正常工作(确实如此)。我在这里做错了什么？

def board_contains_word_in_column(board, word):
    """ (list of list of str, str) -> bool

    Return True if and only if one or more of the columns of the board
    contains word.


    Precondition: board has at least one row and one column, and word is a
    valid word.

    >>> board_contains_word_in_column([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 'NO')
    False
    """


    for char in range(len(board)):
        if word in make_str_from_column(board,char):
            return True

    return False

Answer 1

len(board) 是 2。我怀疑你的意思是 len(board[0]) 是 4

这里有一个更简单的方法来编写你的函数的提示

>>> board = [['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']]
>>> tuple('NO') in zip(*board)
False
>>> tuple('NS') in zip(*board)
True