python - 使用列表获取平均值

Question

这个程序应该要求用户输入 12 个月的月降雨量，计算并计算全年降雨量、月平均降雨量以及最高和最低降雨量的月份。

我可以让它要求输入，给出每年的总计和每月的平均数，但我觉得好像程序的输入部分应该以某种方式减少，它看起来太大太笨重，我不能完全弄清楚如何获得高/低平均值。任何帮助将非常感激。提前致谢。

def main():
    jan = int(input('Enter Rainfall For January: '))
    feb = int(input('Enter Rainfall for February: '))
    mar = int(input('Enter Rainfall For March: '))
    april = int(input('Enter Rainfall For April: '))
    may = int(input('Enter Rainfall For May: '))
    june = int(input('Enter Rainfall For June: '))
    jul = int(input('Enter Rainfall For July: '))
    aug = int(input('Enter Rainfall For August: '))
    sept = int(input('Enter Rainfall For September: '))
    oct = int(input('Enter Rainfall For October: '))
    nov = int(input('Enter Rainfall For November: '))
    dec = int(input('Enter Rainfall For Deceember: '))
    totalyear = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec
    print('The total for the year is: ',totalyear)
    avg = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec / 12
    print('The average monthly rainfall is: ',avg)
main()

Answer 1

您可以使用列表和循环。 :)

def main():
    months = ["Jan","Feb" .... ,"Dec"]
    rain = []
    for month in months:
        rain.append(int(input("Enter .. for" + month)))
    print("Total", sum(rain))
    print("Average", sum(rain)/float(len(rain)))

同样，对于最大值和最小值，您可以使用 max(rain) 和 min(rain)。