Python:匹配某些术语的字符串

Question

我有一个推文列表，我必须从中选择包含“促销”、“折扣”或“优惠”等术语的推文。此外，我需要通过识别诸如“%”、“Rs.”、“$”等内容来查找宣传某些交易(如折扣)的推文。我对正则表达式一无所知，而且文档也无济于事。这是我的代码。这很糟糕，但请原谅

import pymongo
import re
import datetime
client  = pymongo.MongoClient()
db = client .PWSocial
fourteen_days_ago = datetime.datetime.utcnow() - datetime.timedelta(days=14)
id_list = [57947109, 183093247, 89443197, 431336956]
ar1 = [" deal "," deals ", " offer "," offers " "discount", "promotion", " sale ", " inr", " rs", "%", "inr ", "rs ", " rs."]
def func(ac_id):
    mylist = []
    newlist = []
    tweets = list(db.tweets.find({'user_id' : ac_id, 'created_at': { '$gte': fourteen_days_ago }}))
    for item in tweets:
        data = item.get('text')
        data = data.lower()
        data = data.split()
        flag = 0
        if set(ar1).intersection(data):
            flag = 1
        abc = []
        for x in ar1:
            for y in data:
                    if re.search(x,y):
                        abc.append(x)
                        flag = 1
                        break
        if flag == 1:
            mylist.append(item.get('id'))
            newlist.append(abc)
    print mylist
    print newlist
for i in id_list:
    func(i)

这段代码没有给我任何正确的结果，而且作为正则表达式的菜鸟，我不知道它有什么问题。谁能建议更好的方法来完成这项工作？感谢您的帮助。

Answer 1

我的第一个建议——学习正则表达式，它赋予你无限的文本处理能力。

但是，为了给你一些可行的解决方案(并作为进一步探索的起点)试试这个:

import re

re_offers = re.compile(r'''
    \b  # Word boundary
        (?:  # Non capturing parenthesis
            deals?  # Deal or deals
            |  # or ...
            offers?  # Offer or offers
            |
            discount
            |
            promotion
            |
            sale
            |
            rs\.?  # rs or rs.
            |
            inr\d+  # INR then digits
            |
            \d+inr  # Digits then INR
        )  # And group
    \b  # Word boundary
    |  # or ...
    \b\d+%  # Digits (1 or more) then percent
    |
    \$\d+\b  # Dollar then digits (didn't care of thousand separator yet)
    ''',
    re.I|re.X)  # Ignore case, verbose format - for you :)

abc = re_offers.findall("e misio $1 is inr123 discount 1INR a 1% and deal")
print(abc)