python - 如何有条件地从元组列表中删除元素？

Question

>>> x=[("x1","x2","x3"),("x1","x2"),("x2","x3"),("x3","x4")]
>>> x
[('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]

我想删除列表中的元组--x ,if len(x[id])==3 ,len(x[0]==3) ，所以它会被删除，[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')] 是我的想要，我该如何编写代码？

[del element if len(element[id]==3) for id,element in enumerate(x)]

invalid syntax.

Answer 1

使用列表理解来过滤元素，保留所有长度不为 3 的元素:

x = [el for el in x if len(el) != 3]

演示:

>>> x = [('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]
>>> [el for el in x if len(el) != 3]
[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]