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C使用管道传输数据以使用共享内存写入文件

转载 作者:太空宇宙 更新时间:2023-11-04 08:09:56 25 4
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我正在尝试在 C 中使用管道。我有两个在父进程和子进程之间创建两个管道。我必须以 4096 字节的 block 读取文件(如果字节少则更小)并且我必须通过管道读取的数据量和读取次数。比如复制一个6KB文件,父进程将文件的前 4KB 数据写入共享内存,并通过管道将 1 和 4096 两个整数发送给子进程。 child 收到这两个数字,从共享内存复制 4096 字节到输出文件,并通过另一个管道将 1 发送回父。收到1后,parent 将剩下的 2KB 数据复制到共享内存中,并将 2 和 2048 发送给 child。子进程从管道接收它们,将 2048 个字节复制到输出文件,并用 2 回复父进程。然后 parent 将 0, 0 发送给 child 。 child 收到 0 并回复 0,然后退出。 parent 收到 0 并退出。

#include <sys/types.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <sys/wait.h>
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>

#define SIZE 4096
#define NUM_OF_PIPES 2
#define P_READ 0
#define P_WRITE 1
#define C_READ 2
#define C_WRITE 3

int main(int argv, char *argc[]) {


/*Check if program is called correctly*/
if(argv != 3) {
printf("Please call program appropriately\n");
exit(EXIT_FAILURE);
}

FILE *r, *w, *check;
void *sharedMem;
int pipes[4];
int shm;
char userInput[5];
char *name = "dm11ad_cop4610";
int inChild = 0;
int inParent = 0;
r = fopen(argc[1], "rb");
check = fopen(argc[2], "rb");

/*Check if read file can open*/
if(r == NULL) {
perror("Error opening read file");
exit(EXIT_FAILURE);
}
/*Check if write file can open*/
if(check == NULL) {
perror("Error with write file");
exit(EXIT_FAILURE);
}
else {
fseek(check, 0, SEEK_END);
int writeLen = ftell(check);
if(writeLen > 0) {
rewind(check);
printf("Would you like to overwrite file (yes/no): ");
scanf("%s", userInput);
if(!strcmp(userInput, "yes")) {
printf("Overwriting file...\n");
w = fopen(argc[2], "wb");
}
else if(!strcmp(userInput, "no")) {
printf("Will not overwrite\n");
exit(EXIT_FAILURE);
}
else {
printf("User input not accepted\n");
exit(EXIT_FAILURE);
}
}
}

for (int i = 0; i < NUM_OF_PIPES; i++) {
if (pipe(pipes+(i*2)) < 0) {
perror("Pipe");
exit(EXIT_FAILURE);
}
}

/*Check if forking process is successful*/
pid_t pid = fork();
if(pid < 0) {
perror("Fork");
exit(EXIT_FAILURE);
}

shm = shm_open(name, O_CREAT | O_RDWR, S_IRUSR | S_IWUSR);
if(shm == -1) {
perror("Shared memory");
exit(EXIT_FAILURE);
}
if(ftruncate(shm, SIZE) == -1) {
perror("Shared Memory");
exit(EXIT_FAILURE);
}

sharedMem = mmap(NULL, SIZE, PROT_READ | PROT_WRITE, MAP_SHARED, shm, 0);
if(sharedMem == MAP_FAILED) {
perror("Mapping shared memory");
exit(EXIT_FAILURE);
}

if(pid == 0) {
while(inParent);
inChild = 1;
printf("I am in child\n");
close(pipes[P_READ]);
close(pipes[P_WRITE]);
printf("Closed P pipes\n");
int cBytes, len;
printf("Im stuck\n");
len = read(pipes[C_READ], &cBytes, sizeof(cBytes));
printf("There are %i bytes\n", len);
if(len < 0) {
perror("Failed to read from pipe");
exit(EXIT_FAILURE);
}
else if(len == 0) {
printf("End of fle reached\n");
}
else {
printf("Writing to file\n");
fwrite(sharedMem, 1, sizeof(sharedMem), w);
}

printf("Closing C pipes\n");
close(pipes[C_READ]);
close(pipes[C_WRITE]);
printf("Exiting Child\n");
inChild = 0;
}
else {
while(inChild);
inParent = 1;
close(pipes[C_READ]);
close(pipes[C_WRITE]);
int pBytes;

int P2SHM = fread(sharedMem, 1, SIZE, r);
if(P2SHM < 0) {
perror("Could not store to shared memory");
exit(EXIT_FAILURE);
}

if(write(pipes[P_WRITE], &P2SHM, sizeof(int)) < 0) {
perror("Failed to write to pipe");
exit(EXIT_FAILURE);
}

int C2P = read(pipes[P_READ], &pBytes, sizeof(int));
if(C2P < 0) {
perror("Failed to read value from pipe");
exit(EXIT_FAILURE);
}
else if(C2P == 0) {
printf("End of file reached\n");
}
else {
printf("Received succesfully\n");
}

close(pipes[P_READ]);
close(pipes[P_WRITE]);
inParent = 0;
printf("Waiting for child\n");
wait(NULL);
}
return 0;
}

printfs 可以帮助我查看程序在执行过程中的位置。它卡在子进程中,似乎在

期间
 len = read(pipes[C_READ], &cBytes, sizeof(cBytes));

这是一项作业,所以请不要发布代码作为答案,而是请帮助我理解我做错了什么。谢谢

最佳答案

child 和 parent 之间的同步机制看起来很可疑:

while(inParent); 
inChild = 1;

while(inChild);
inParent = 1;

inChildinParent 的初始值为 0。创建子进程后,每个进程都有自己的变量值副本。当您更改 inChild = 1inParent = 1 时,它仅在当前进程内更改。其他进程看不到新值,无法等待输入/输出。

要修复它,您应该使用更好的同步算法,例如处理信号量。阅读"5.2 Processes Semaphores"获取详细信息。

关于C使用管道传输数据以使用共享内存写入文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40184960/

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