python - 以编程方式将列表的内容写入目录

Question

我有一个在 for 循环内生成的 python 列表 ['a','b','c']。我想将列表的每个元素写入一个新文件。

我试过:

counter = 0
for i in python_list:
    outfile = open('/outdirectory/%s.txt') % str(counter) 
    outfile.write(i)
    outfile.close()
    counter += 1 

我得到一个错误:

IOError: [Erno 2] No suchfile or directory. 

如何以编程方式在 for 循环中创建和写入文件？

Answer 1

您没有传递打开模式，因此它试图以读取模式打开。

outfile = open('/outdirectory/%s.txt' % str(counter), "w") 

试试这个:

out_directory = "/outdirectory"
if not os.path.exists(out_directory):
    os.makedirs(out_directory)

for counter in range(0, len(python_list)):
    file_path = os.path.join(out_directory, "%s.txt" % counter)
    with open(file_path, "w") as outfile:
        outfile.write(python_list[counter])