c - 具有动态字符的结构**，在添加第 5 个条目后将第一个字符 * 显示为空白

Question

我有一个动态字符、短裤和整数数组的结构。当我更新大小时，一切都达到 4 大小。当我添加一个条目时，出于某种原因，动态 char 数组的第一个条目最终显示为空白而不是 chars 我在期待。

但是，如果我实例化一个包含 5 个以上条目的结构，我没有问题。

这是怎么回事？以下是我的代码以及记录到我的终端的内容

typedef struct network {
  int count;
  char **ips;
  short *ports;
  int *heartbeat;
  int *local_time;
} network;

network *create_network(char *ip, short port) {
  network *n = malloc(sizeof(network));
  n->count = 1;
  n->ips = malloc(sizeof(char *));
  n->ports = malloc(sizeof(short));
  n->heartbeat = malloc(sizeof(int));
  n->local_time = malloc(sizeof(int));

  n->ips[0] = malloc(INET_ADDRSTRLEN);
  memset(n->ips[0], '\0', INET_ADDRSTRLEN);
  strcpy(n->ips[0], ip);
  n->ports[0] = port;
  n->heartbeat[0] = 0;
  n->local_time[0] = 0;
  return n;
}

void update_network(network *current, network *new, int local_time) {

  current->count++;
  current->ips = realloc(current->ips, sizeof(char *) * current->count);
  current->ips[current->count - 1] = malloc(INET_ADDRSTRLEN);
  strcpy(current->ips[current->count - 1], new->ips[0]);

  current->ports = realloc(current->ports, sizeof(short) * current->count);
  current->ports[current->count - 1] = new->ports[0];

  current->heartbeat =
      realloc(current->heartbeat, sizeof(int) * current->count);
  current->heartbeat[current->count - 1] = new->heartbeat[0];

  printf("after heartbeat: %s:%i\n", current->ips[0], current->ports[0]);

  current->local_time[current->count - 1] = local_time;
  printf("after localtime: %s:%i\n", current->ips[0], current->ports[0]);
}

int main(int argv, char **argc) {
  char *ip = malloc(INET_ADDRSTRLEN);
  ip = "0.0.0.0";

  network *n1 = create_network(ip, 80);
  network *n2 = create_network(ip, 81);
  network *n3 = create_network(ip, 82);
  network *n4 = create_network(ip, 83);
  network *n5 = create_network(ip, 84);

  update_network(n1, n2, 10);
  update_network(n1, n3, 11);
  update_network(n1, n4, 11);
  update_network(n1, n5, 11);
}

日志(注意到最后一个日志中出现的随机空行吗？)

after heartbeat: 0.0.0.0:80
after localtime: 0.0.0.0:80
after heartbeat: 0.0.0.0:80
after localtime: 0.0.0.0:80
after heartbeat: 0.0.0.0:80
after localtime: 0.0.0.0:80
after heartbeat: 0.0.0.0:80
after localtime:
                 :80

Answer 1

在分配 current->local_time[current->count - 1] = local_time; .