c - 知道一个月中的日期，其中一天出现在 c 中

Question

我正在尝试打印某一天所在月份的日期。为此，我需要获取日期的整数值，例如星期日为 0，星期一为 1，星期二为 2 等。我如何在 C 中执行此操作？每当我尝试时，我似乎都会出错。

#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>
int main(){
int days[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
  int year, day, month, date, a, y, m, s, i, b=0;
  char week[7][10] ;

 strcpy(week[0], "Sunday") ;
 strcpy(week[1], "Monday") ;
 strcpy(week[2], "Tuesday") ;
 strcpy(week[3], "Wednesday") ;
 strcpy(week[4], "Thursday") ;
 strcpy(week[5], "Friday") ;
 strcpy(week[6], "Saturday") ; 
 //char *week[]={"Sunday","Monday","Tuesday","Wednesday",
            //"Thrusday","Friday","Saturday"};
  printf("Enter the day:");
  scanf("%s",week[i]);
  printf("Enter the month:");
  scanf("%d",&month);
  printf("Enter the year:");
  scanf("%d",year);
  if(year%4==0&&year%100!=0||year%400==0)
  days[2]==
  29;
  else
  days[2]==28;

  //for(i=1;i<7;i++)
  //week[i]=i;
  //i=i+1;
  week[0]==0;
  week[1]==1;
  week[2]==2;
  week[3]==3;
  week[4]==4;
  week[5]==5;
  week[6]==6;

  //algorithm from http://www.tondering.dk/claus/cal/chrweek.php#calcdow
  a = (14 - month) % 12;
  y = year - a;
  m = month + (12 * a) - 12;

  date = (week[i] + y + (y / 4) - (y / 100) + (y / 400) + ((31 * m) / 12)) % 7 ;
  printf("%d",date);

  for(day=1; day<=days[month] ;day++)
  {
   date=date+7;
   date++;
  }
  return 0;
   }

Answer 1

在第一个 scanf 中，i 没有值。 week[0]、week[1] 等是字符数组。你想通过将它们与 int 进行比较来做什么？ (周[0]==0....)。

  declare a char[10] wordday;
  printf("Enter the day:");
  scanf("%s",wordday);




  for(i=0;i<7;i++)
      if(strcmp(wordday,week[i])==0)
      {
      printf("%d",i);
      break;
      }