C 指针参数不匹配编译警告

Question

来自一个非常生疏的 C 想成为程序员的快速问题。我有以下场景

avr-gcc -Wall -Os -DF_CPU=8000000 -mmcu=atmega328p -c mirf.c -o mirf.o mirf.c: In function ‘mirf_config’: mirf.c:76:20: warning: passing argument 1 of ‘mirf_set_TADDR’ from incompatible pointer type mirf_set_TADDR(&addr); ^ In file included from mirf.c:27:0: mirf.h:52:13: note: expected ‘uint8_t *’ but argument is of type ‘uint8_t (*)[5]’ extern void mirf_set_TADDR(uint8_t * adr);

void mirf_config() 
// Sets the important registers in the MiRF module and powers the module
// in receiving mode
{

uint8 addr[5] = {0xA0,0xA1,0xA2,0xA3,0xA4};       
mirf_set_TADDR(&addr); // HERE!!

// Set RF channel
mirf_config_register(RF_CH,mirf_CH);

// Set length of incoming payload 
mirf_config_register(RX_PW_P0, mirf_PAYLOAD);

// Start receiver 
PTX = 0;        // Start in receiving mode
RX_POWERUP;     // Power up in receiving mode
mirf_CE_hi;     // Listening for pakets

}

void mirf_set_TADDR(uint8_t * adr)
// Sets the transmitting address
{
    mirf_write_register(TX_ADDR, adr,5);
}

如何消除警告并将指针正确发送到 5 个字节？

谢谢!!

Answer 1

你需要知道的就在这里:

mirf.h:52:13: note: expected ‘uint8_t ’ but argument is of type ‘int ()[5]’ extern void mirf_set_TADDR(uint8_t * adr);

mirf_set_TADDR 函数需要一个指向 uint8_t 的指针(即 uint8_t *)，但您向它传递的是一个数组(即 uint8_t (*)[5])。当传递给函数时，数组会衰减到第一个元素的地址，因此去掉寻址运算符:

mirf_set_TADDR(addr);