python - 计算文件中的大写字母、小写字母、数字和空格

Question

我的任务是计算 .txt 文件中的大写、小写、数字和空白字符。

我尝试了多种方法，但似乎不太正确。我不知道我要去哪里。

这是我得到的输出:

大写计数为0小写计数为 0位数为0空白计数为 0

代码:

def main():

    uppercase_count = 0
    lowercase_count = 0
    digits_count = 0
    whitespace_count = 0

    uppercase =['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
    lowercase = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
    digits = ['0','1','2','3','4','5','6','7','8','9']
    whitespace = [' ']

    infile = open("text.txt", "r")

    data = infile.readlines()

    for character in data:
        if character in uppercase:
            uppercase_count += 1

    for character in data:
        if character in lowercase:
            lowercase_count += 1

    for character in data:
        if character in digits:
            digits_count += 1

    for character in data:
        if character in whitespace:
            whitespace_count += 1

    print('The uppercase count is',uppercase_count)
    print('The lowercase count is',lowercase_count)
    print('The digit count is',digits_count)
    print('The whitespace count is',whitespace_count)

main()

Answer 1

你可以简单地使用内置函数

for character in data:
    if character.isupper():
        uppercase_count += 1
    elif character.islower():
        lowercase_count += 1
    elif character.isspace():
        whitespace_count +=1
    elif character.isdigit():
        digit_count +=1

您也可以使用以下命令计算每一行的字符数。

digit_count,whitespace_count,lowercase_count,uppercase_count=0,0,0,0
lines = infile.readlines()
for data in lines:
    for character in data:
        if character.isupper():
            uppercase_count += 1
        elif character.islower():
            lowercase_count += 1
        elif character.isspace():
            whitespace_count +=1
        elif character.isdigit():
            digit_count +=1