python - 每次在python中迭代时如何将循环结果附加到数组中

Question

我一直在研究这个程序，任何形式的帮助都将不胜感激。
查找两年之间的闰年并将其添加到数组中的程序...

from array import array

x=int(input("Enter the year "))
print("the year you entered is",x)

while x<=2017:
    if x%4==0:
        print(x)
        n=array('i',[x])
        n.append(x)
        x=x+1
    else:
        x=x+1
print(n)

输出

enter the year 1992
the year you entered is 1992
1992
1996
2000
2004
2008
2012
2016
array('i', [2016, 2016])

Answer 1

问题是每当一年被 4 整除时，您都会重新设置数组的值。您要做的是在循环外声明数组。

from array import array

x=int(input("enter the year from which you want to know the leap year from"))
print("the year you entered is",x)

n=array('i')
while x<=2017:
    if (x % 4 == 0 and x % 100 != 0) or x % 400 == 0:
        print(x)   
        n.append(x)
    x += 1  # we need to add 1 regardless, no need for else  
print(n)
# output: array('i', [1992, 1996, 2000, 2004, 2008, 2012, 2016])