c - 我正在尝试使用 C 程序查找单词的拼字游戏值

Question

我总是将输入的每个字母的值设为 1，而我应该按照代码中的描述获取值。请帮助找出我的代码中的错误。

#include <stdio.h>
#include <ctype.h>

char c;

char num (char c);

int main () {
    int sum;

    printf("Enter a word:");

    c=0;

        while (c=getchar() != '\n') {
            c=toupper(c);
            sum+=c;
        }

    printf("Scrabble value : %d",sum);

    return(0);
}

char num (char c) {

    if (c=='A'||c=='E'||c=='I'||c=='L'||c=='N'||c=='O'||c=='R'||c=='S'||c=='T'||c=='U') c=1;
    if (c=='D'||c=='G') c=2;
    if (c=='B'||c=='C'||c=='M'||c=='P') c=3;
    if (c=='F'||c=='H'||c=='V'||c=='W'||c=='Y') c=4;
    if (c=='K') c=5;
    if (c=='J'||c=='X') c=8;
    if (c=='Q'||c=='Z') c=10;

    return(c);
}

Answer 1

简而言之，这对你有用(调用 num；修复了 while 中的 getchar 调用；将总和初始化为 0；无错误处理):

#include <stdio.h>
#include <ctype.h>

char c;

char num (char c);

int main () {
    int sum = 0;

    printf("Enter a word:");

    c=0;

        while ((c=getchar()) != '\n') {
            c=toupper(c);
            sum+=num(c);
        }

    printf("Scrabble value : %d",sum);

    return(0);
}

char num (char c) {

    if (c=='A'||c=='E'||c=='I'||c=='L'||c=='N'||c=='O'||c=='R'||c=='S'||c=='T'||c=='U') c=1;
    if (c=='D'||c=='G') c=2;
    if (c=='B'||c=='C'||c=='M'||c=='P') c=3;
    if (c=='F'||c=='H'||c=='V'||c=='W'||c=='Y') c=4;
    if (c=='K') c=5;
    if (c=='J'||c=='X') c=8;
    if (c=='Q'||c=='Z') c=10;

    return(c);
}