c - 如何在 C 中更改进程的十六进制转储

Question

我写这段代码来改变选定进程的十六进制转储，这里是代码:

#include <windows.h>

int main(int argc, char *argv[])
{
unsigned char buffer[5];
int i;
unsigned char patchbytes[5] = { 0xCC, 0xCC, 0xCC, 0xCC, 0xCC};

DWORD pid = atoi(argv[1]);

HANDLE hproc = OpenProcess(PROCESS_ALL_ACCESS, FALSE, pid);

if (!hproc)
{
    printf("open failed\n");
    return -1;
}

ReadProcessMemory(hproc, (void*)0x77992FF5, buffer, 5, NULL);

printf("Before:\n");
for (i = 0; i < sizeof(patchbytes); i++) {

    printf("%02x \t", buffer[i]);

}

printf("\n");
WriteProcessMemory(hproc, (void*)0x77992FF5, patchbytes, 5, NULL);

printf("After:\n");
for (i = 0; i < sizeof(patchbytes); i++) {

    printf("%02x \t", buffer[i]);

}

FlushInstructionCache(hproc, NULL, 0);

CloseHandle(hproc);

return 0;

}

所以我读取前五个字节，然后覆盖它，检查覆盖前后字节的值。但它给我的是一样的，所以字节没有改变。我做错了什么？

Answer 1

您只需将最初读取的缓冲区打印两次。

在 WriteProcessMemory 之后加入另一个 ReadProcessMemory(hproc, (void*)0x77992FF5, buffer, 5, NULL);。