c - 我怎样才能让数组从用户那里读取？

Question

我想要的只是数组 foo 的用户输入，并从中向左和向右打印 op。

我尝试添加以下代码，但无法得到相同的结果。

我没有写 char foo [29] = "1021+2551";，而是写了:

int i;

printf("Enter the number and opperator");

for(i=0; i<1; i++)      // I used i < 1 b/c I want to get only one line input

{

scanf("%c", foo[i]);

}

void main(){

    int index;
    char foo[29] = "1021+2551";
    int len = strlen(foo);

    for (int i=0; i < len; i++)
    {
    if(foo[i] == '+' || foo[i] == '-' || foo[i] == '*' || foo[i] == '/' || foo[i] == '%'){
       char op = foo[i];
       printf("%c", op);
       index = i;
        }
    }
    char left;
    for(int j=0; j < index; j++){
       left = printf("%c",foo[j]);
    }
    char right;
    for(int k=index + 1; k < len; k++){
       right = printf("%c",foo[k]);
    }
}

如果我在用户输入中输入 100+200，结果应该是

+100200

Answer 1

像这样简单快捷的东西:)

    int main(){

    int i;
    char foo[29];

    printf("Enter the number and opperator\n");
    fgets(foo, 29 , stdin);

    int index;
    int len = strlen(foo);

    for (int i=0; i < len; i++)
    {
    if(foo[i] == '+' || foo[i] == '-' || foo[i] == '*' || foo[i] == '/' || foo[i] == '%'){
       char op = foo[i];
       printf("%c", op);
       index = i;
        }
    } printf(" ");
    char left;
    for(int j=0; j < index; j++){
       left = printf("%c",foo[j]);
    } printf(" ");
    char right;
    for(int k=index + 1; k < len; k++){
       right = printf("%c",foo[k]);
    }
    return 0;
}