c - 如何从矩阵打印行/列/对角线

Question

我试图让我的程序打印出不等于幻方规则的行、列或对角线，例如，如果矩阵是

1 9 5

2 4 3

6 8 7

第 1 行 [2, 4, 3] 不起作用

第 2 行 [6, 8, 7] 不起作用

第 0 列 [1, 2, 6] 不起作用

对角线 1 [1, 4, 7] 不起作用

我试过 print("%d", matrix[row])

#include <stdio.h>
#include <stdbool.h>
#include <unistd.h>

int main()
{
  //declared variables
  int size = 3;
  int matrix[3][3];
  int row, column = 0;
  int sum0, sum1, sum2;
  int flag = 0;

  //ask user to input 1-9 and scans it
  printf("Enter in the values: \n");
    for (row = 0; row < size; row++){
      for (column = 0; column < size; column++)

      scanf("%d", &matrix[row][column]);
    }

  //enters number into magic square format
  printf("You entered: \n");
  for (row = 0; row < size; row++) {
    printf("\n");
    for (column = 0; column < size; column++) {
      printf("%d ", matrix[row][column]);
    }
  }

  //diagonal calculations
  sum0 = 0;
  for (row = 0; row < size; row++) {
    for (column = 0; column < size; column++) {
      if (row == column)
        sum0 = sum0 + matrix[row][column];
    }
  }

  //row calculations
  for (row = 0; row < size; row++) {
    sum1 = 0;
    for (column = 0; column < size; column++) {
      sum1 = sum1 + matrix[row][column];
    }
    if (sum0 == sum1)
      flag = 1;
    else {
      flag = 0;
      break;
    }
  }

  //column calculations
  for (row = 0; row < size; row++) {
    sum1 = 0;
    for (column = 0; column < size; column++) {
      sum2 = sum2 + matrix[row][column];
    }
    if (sum1 == sum2)
      flag = 1;
    else {
      flag = 0;
      break;
    }
  }    

printf("\nAnalyzing...\n");



if (flag == 1) {
  sleep(2);
  printf("This is a magic square!\n");
}
else {
  sleep(2);


  printf("This is not a magic square!\n");
  }


return 0;
}

Answer 1

您必须使用循环来分别打印每个字符。printf(3) 无法打印整数数组。