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java - 使用 ImageIO.write 时出现 OutOfMemory

转载 作者:太空宇宙 更新时间:2023-11-04 07:42:21 27 4
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即使 BlockingQueue 为空,我的 saveScreenShot 线程上也会出现 OutOfMemory 错误

在我的 Main 中有以下变量存储图像

public static BlockingQueue<ImageSaveData> imageQueue1 = new LinkedBlockingQueue<ImageSaveData>();
public static BlockingQueue<ImageSaveData> imageQueue2 = new LinkedBlockingQueue<ImageSaveData>();
public static BlockingQueue<ImageSaveData> imageQueue3 = new LinkedBlockingQueue<ImageSaveData>();
public static BlockingQueue<ImageSaveData> imageQueue4 = new LinkedBlockingQueue<ImageSaveData>();

这是我的 ImageSaveData 类

import java.awt.image.BufferedImage;

public class ImageSaveData
{
private String fileNumber;
private BufferedImage image;

public ImageSaveData(String fileNumber, BufferedImage image)
{
this.fileNumber = fileNumber;
this.image = image;
}

public String getFileNumber()
{
return fileNumber;
}

public BufferedImage getImage()
{
return image;
}
}

这是我的线程,它截取屏幕截图并将其保存到 imageQueueX

    // long start = System.currentTimeMillis();
synchronized (runner)
{
int imageCount = 0;
int maxCount = 0;
boolean hasMessage = false;
String[] countFormat =
{
"00000000", "0000000", "000000", "00000", "0000", "000", "00", "0"
};
// 10
while (true)
{
if (maxCount++ < 1000000010)
{
try
{
BufferedImage image = new Robot().createScreenCapture(new Rectangle(Toolkit.getDefaultToolkit().getScreenSize()));
String imageOutNumb = "";
if (imageCount < 10) imageOutNumb = countFormat[0] + imageCount++;
else if (imageCount < 100) imageOutNumb = countFormat[1] + imageCount++;
else if (imageCount < 1000) imageOutNumb = countFormat[2] + imageCount++;
else if (imageCount < 10000) imageOutNumb = countFormat[3] + imageCount++;
else if (imageCount < 100000) imageOutNumb = countFormat[4] + imageCount++;
else if (imageCount < 1000000) imageOutNumb = countFormat[5] + imageCount++;
else if (imageCount < 10000000) imageOutNumb = countFormat[6] + imageCount++;
else if (imageCount < 100000000) imageOutNumb = countFormat[7] + imageCount++;
else imageOutNumb = "" + imageCount++;

ImageSaveData imageSaveData = new ImageSaveData(imageOutNumb, image);

while (true)
{
if (Main.imageQueue1.offer(imageSaveData, 1, TimeUnit.NANOSECONDS)) break;
if (Main.imageQueue2.offer(imageSaveData, 1, TimeUnit.NANOSECONDS)) break;
if (Main.imageQueue3.offer(imageSaveData, 1, TimeUnit.NANOSECONDS)) break;
if (Main.imageQueue4.offer(imageSaveData, 1, TimeUnit.NANOSECONDS)) break;
}
}
catch (HeadlessException | AWTException e)
{
e.printStackTrace();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
catch(OutOfMemoryError e)
{
try
{
runner.sleep(1);
}
catch (InterruptedException e1)
{
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
try
{
runner.sleep(34);
}
catch (InterruptedException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else
{
if (hasMessage)
{
try
{
System.out.println(Main.imageQueue1.isEmpty());
System.out.println(Main.imageQueue2.isEmpty());
System.out.println(Main.imageQueue3.isEmpty());
System.out.println(Main.imageQueue4.isEmpty());
}
catch (Exception e)
{

}
}
else
{
System.out.println("We Have Finished saving images to memory");
hasMessage = true;
}
}
}
}

我有 3 个消费者线程,唯一的区别是文件路径不同

    // long start = System.currentTimeMillis();
synchronized (runner)
{
String PathName = "\\\\DELL\\Maxtor\\aJordan\\";
while (true)
{
try
{
ImageSaveData imageData1 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData2 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData3 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData4 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
if (imageData1 != null) ImageIO.write(imageData1.getImage(), "png", new File(PathName + imageData1.getFileNumber() + ".png"));
if (imageData2 != null) ImageIO.write(imageData2.getImage(), "png", new File(PathName + imageData2.getFileNumber() + ".png"));
if (imageData3 != null) ImageIO.write(imageData3.getImage(), "png", new File(PathName + imageData3.getFileNumber() + ".png"));
if (imageData4 != null) ImageIO.write(imageData4.getImage(), "png", new File(PathName + imageData4.getFileNumber() + ".png"));


}
catch (InterruptedException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}

错误

java.lang.OutOfMemoryError: Java heap space
at sun.awt.windows.WRobotPeer.getRGBPixels(Unknown Source)
at java.awt.Robot.createScreenCapture(Unknown Source)
at TakeShothandler1.run(TakeShothandler1.java:48)
at java.lang.Thread.run(Unknown Source)

第 48 行是

BufferedImage image = new Robot().createScreenCapture(new Rectangle(Toolkit.getDefaultToolkit().getScreenSize()));

最佳答案

您的队列容量是多少?当前堆大小是多少?

每个屏幕截图的大小约为 3-10 MB,具体取决于您的分辨率(例如 1024x768x32 分辨率:1024x768x4bytes/pixel=3.14MB),并且您获取它们的速度可能比将它们写入磁盘的速度更快。

根据您的堆大小和队列容量,清理可用堆可能根本不需要很长时间。

另外,我不确定(您可能在其他地方有其他代码),但看起来您可能只从消费者线程中的一个队列进行轮询:

ImageSaveData imageData1 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData2 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData3 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);
ImageSaveData imageData4 = Main.imageQueue1.poll(1, TimeUnit.NANOSECONDS);

编辑:哇,没有意识到这个帖子已经有两年了。

关于java - 使用 ImageIO.write 时出现 OutOfMemory,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15858880/

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