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我正在尝试解决一个问题:Django 告诉我我的 View 不存在,但我创建了一个应该以相同名称加载的 View 。我有以下错误:
ViewDoesNotExist at /
Could not import Gastenboek.views.main.as_view(). Parent module
Gastenboek.views.main does not exist.
traceback
Environment:
Request Method: GET
Request URL: http://127.0.0.1:8000/
Django Version: 1.6.1
Python Version: 3.3.3
Installed Applications:
('django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'Gastenboek')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware')
Traceback:
File "C:\Python33\lib\site-packages\django\core\handlers\base.py" in get_response
101. resolver_match = resolver.resolve(request.path_info)
File "C:\Python33\lib\site-packages\django\core\urlresolvers.py" in resolve
320. sub_match = pattern.resolve(new_path)
File "C:\Python33\lib\site-packages\django\core\urlresolvers.py" in resolve
222. return ResolverMatch(self.callback, args, kwargs, self.name)
File "C:\Python33\lib\site-packages\django\core\urlresolvers.py" in callback
229. self._callback = get_callable(self._callback_str)
File "C:\Python33\lib\site-packages\django\utils\functional.py" in wrapper
32. result = func(*args)
File "C:\Python33\lib\site-packages\django\core\urlresolvers.py" in get_callable
103. (lookup_view, mod_name))
Exception Type: ViewDoesNotExist at /
Exception Value: Could not import Gastenboek.views.main.as_view(). Parent module Gastenboek.views.main does not exist.
观看次数
from django.shortcuts import render
from django.views.generic import ListView
from Gastenboek.models import *
class main(ListView):
model = Bericht
template_name = 'template/bericht_lijst.html'
paginate_by = 10
context_object_name = "bericht_lijst"
# Create your views here.
模型
from django.db import models
from django.contrib.auth.models import User
from django.contrib import admin
class Bericht(models.Model):
titel = models.CharField(max_length=50)
auteur = models.ForeignKey(User, blank=True)
email = models.EmailField(max_length=75)
inhoud = models.TextField(max_length=10000, blank=True)
datum = models.DateTimeField(auto_now_add=True)
def __str__(self):
return str(self.auteur) + " : " + str(self.titel)
class Meta:
verbose_name_plural = "berichten"
class BerichtAdmin(admin.ModelAdmin):
list_display = ["auteur", "datum", "titel"]
list_filter = ["datum", "auteur"]
admin.site.register(Bericht, BerichtAdmin)
网址.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'Niels.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^admin/', include(admin.site.urls)),
(r"^(\d+)/$",'Gastenboek.views.main.as_view()'),
(r"", 'Gastenboek.views.main.as_view()'),
)
最佳答案
不要在 .as_view() 中使用引号
from GastenBoek import views
(r"^(\d+)/$", views.main.as_view()),
(r"", views.main.as_view()),
关于python - Django 中的 ViewDoesNotExist,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21588029/
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