python - Matplotlib:将原点移动到左上角

Question

在 Matlab 中，绘制原点在左上角，x 轴为原点南正，y 轴为原点东； x 轴在左边距上编号，y 轴在上边距上标记。

figure();
set(gca,'YAxisLocation','Right','YDir','reverse')
axis([0 10 0 10]);
daspect([1,1,1])
grid on
view([-90 -90])

如何在 Python 中实现相同的功能？我是这样进行的:

import matplotlib.pyplot as plt
plt.figure(1)

plt.axis([40, 160, 0, 0.03])
plt.grid(True)
plt.show()

Python 的等价物是什么:

1. set(gca,'YAxisLocation','Right','YDir','reverse')
2. daspect([1,1,1])
3. 查看([-90 -90])

编辑:

figure
set(gca,'YAxisLocation','right','XTick',0:15,'YDir','reverse')
axis([0 16 0 16]);
daspect([1,1,1])
hold on
text(2,8,'CHN');
text(8,2,'USA');
view([-90 -90])

输出是:

Answer 1

这是一个注释示例，显示了如何反转轴并将刻度移动到顶部、设置网格状态并模仿 view() 命令:

import matplotlib.pyplot as plt
import numpy as np

plt.figure()    
plt.axis([0, 16, 0, 16])     
plt.grid(False)                         # set the grid
data= [(8,2,'USA'), (2,8,'CHN')]

for obj in data:
    plt.text(obj[1],obj[0],obj[2])      # change x,y as there is no view() in mpl


ax=plt.gca()                            # get the axis
ax.set_ylim(ax.get_ylim()[::-1])        # invert the axis
ax.xaxis.tick_top()                     # and move the X-Axis      
ax.yaxis.set_ticks(np.arange(0, 16, 1)) # set y-ticks
ax.yaxis.tick_left()                    # remove right y-Ticks

图片: