python - Django 1.8.2 和 dumpdata 的 simplejson 错误

Question

命令:

% ./manage.py dumpdata

输出:

CommandError: Unable to serialize database: cannot import name simplejson

zc.buildout 配置为在 app 目录下安装 simplejson。 simplejson 也存在于我的自定义 Python 目录/usr/local/python 中。

感谢您的帮助!

堆栈跟踪:

% ./manage.py dumpdata --traceback
Traceback (most recent call last):
  File "./manage.py", line 25, in <module>
    sys.exit(djangorecipe.manage.main('project.settings.settings_dev'))
  File "/opt/project/eggs/djangorecipe-1.11-py2.7.egg/djangorecipe/manage.py", line 9, in main
    management.execute_from_command_line(sys.argv)
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/management/__init__.py", line 338, in execute_from_command_line
    utility.execute()
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/management/__init__.py", line 330, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/management/base.py", line 390, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/management/base.py", line 441, in execute
    output = self.handle(*args, **options)
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/management/commands/dumpdata.py", line 162, in handle
    stream=stream or self.stdout)
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/serializers/__init__.py", line 128, in serialize
    s = get_serializer(format)()
  File "/opt/project/eggs/Django-1.8.2-py2.7.egg/django/core/serializers/__init__.py", line 51, in __call__
    raise self.exception
ImportError: cannot import name simplejson

Answer 1

django.utils.simplejson，不要与 simplejson 混淆模块是 deprecated在django 1.7中，我们现在依赖于python内置的json。如果您正在运行遗留的第三方代码，或者一些难以更改的代码，请执行此操作

try:
    import django.utils.simplejson
except:
    import json as simplejson

如果您正在编写新代码，请编写此代码以实现向后兼容性:

try:
    import json
except:
    import django.utils.simplejson as json

在您的情况下，是 manage.py 抛出错误还是代码中其他地方的错误？你能发布堆栈跟踪吗？