C:掷骰子/骰子游戏

Question

这段代码的用途:模拟100场CRAPS，记录第一轮输，第一轮赢，第二轮负加分，第二轮赢加分的#。

那些不熟悉掷骰子规则的人；您基本上掷两个骰子，如果结果不是 2、3 或 12 的总数，您可以再次掷骰(您在该轮掷的数字将保留并添加到您的积分中)。如果您掷出 7 或 11，您将自动获胜。

这是我目前所处的位置:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>

int main ()
{
int i,d1,d2,sumd,sumd2;
double winf = 0, lostf = 0, winp = 0, lostp = 0;
printf("This program will simulate the game of craps for 100 times.\n");

for (i=0; i<100; i++) {
    d1 = rand()%6+1;
    d2 = rand()%6+1;
    sumd = d1 + d2;

    if (sumd==7 || sumd==11) {
        printf("You rolled a 7 or an 11, you win.\n");
        winf++;
    }
    if (sumd==2 || sumd==3 || sumd==12) {
        printf("You rolled a 12, a 3, or a 2, you lose.\n");
        lostf++;
    }
    if (sumd==4 || sumd==5 || sumd==6 || sumd==8 || sumd==9 || sumd==10) {
        while (1) {
            d1 = rand()%6+1;
            d2 = rand()%6+1;
            sumd2 = d1 + d2;

            if (sumd2==sumd){ 
                printf("You rolled your points, you win.\n");
                winp++;
            break;}
            if (sumd==7){ 
                printf("You rolled a 7, you lose.\n");
                lostp++;
            break;}
        }
    }
}

printf("First roll wins: %lf, First roll loses: %lf, Second roll wins: %lf, Second roll loses: %lf. ", winf, lostf, winp, lostp);
}

我只要求你给我一些选择，让我知道如何保留这些要在最后打印的点？？

此外，我觉得我的代码可以写得更好，减少冗余，有什么建议吗？

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>

int main ()
{
int i,d1,d2,sumd,sumd2;
double winf = 0, lostf = 0, winp = 0, lostp = 0;

printf("This program will simulate the game of craps for 100 times. Press any key to continue.\n");
//getchar();

for (i=0; i<100; i++) {
    d1 = rand()%6+1;
    d2 = rand()%6+1;
    sumd = d1 + d2;

switch(sumd){
    case 7:
    case 11:
        printf("You rolled %d, you win.\n", sumd);
        winf++;
        break;
    case 2:
    case 3:
    case 12:
        printf("You rolled %d, you lose.\n", sumd);
        lostf++;
        break;
    default:
        while (1) {
            d1 = rand()%6+1;
            d2 = rand()%6+1;
            sumd2 = d1 + d2;

            if (sumd2==sumd){ 
                printf("You rolled your points(%d), you win.\n",sumd);
                winp++;
            break;}
            if (sumd2==7){ 
                printf("You rolled a 7, you lose.\n");
                lostp++;
            break;}
        }
}

}
printf("First roll wins: %lf, First roll loses: %lf, Second roll wins: %lf, Second roll loses: %lf. \n", winf, lostf, winp, lostp);
}

Answer 1

你可以很容易地压缩

的两次出现

d1 = rand()%6+1;
d2 = rand()%6+1;
sumd2 = d1 + d2;

进入一个函数:

int rolldice(){
    int d1,d2;
    d1 = rand()%6+1;
    d2 = rand()%6+1;
    return d1 + d2;
}

或者单行形式:

int rolldice(){
    return (rand()%6)+(rand()%6)+2;
}

然后你会写

sumd = rolldice();