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python - scipy 稀疏矩阵除法

转载 作者:太空宇宙 更新时间:2023-11-04 07:33:27 30 4
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我一直在尝试将 python scipy 稀疏矩阵除以其行的向量和。这是我的代码

sparse_mat = bsr_matrix((l_data, (l_row, l_col)), dtype=float)
sparse_mat = sparse_mat / (sparse_mat.sum(axis = 1)[:,None])

然而,无论我如何尝试,它都会抛出错误

sparse_mat = sparse_mat / (sparse_mat.sum(axis = 1)[:,None])
File "/usr/lib/python2.7/dist-packages/scipy/sparse/base.py", line 381, in __div__
return self.__truediv__(other)
File "/usr/lib/python2.7/dist-packages/scipy/sparse/compressed.py", line 427, in __truediv__
raise NotImplementedError
NotImplementedError

有人知道我哪里出错了吗?

最佳答案

您可以通过从行总和的倒数创建一个稀疏对角矩阵,然后将其与您的矩阵相乘来规避这个问题。在产品中,对角矩阵向左,您的矩阵向右。

例子:

>>> a
array([[0, 9, 0, 0, 1, 0],
[2, 0, 5, 0, 0, 9],
[0, 2, 0, 0, 0, 0],
[2, 0, 0, 0, 0, 0],
[0, 9, 5, 3, 0, 7],
[1, 0, 0, 8, 9, 0]])
>>> b = sparse.bsr_matrix(a)
>>>
>>> c = sparse.diags(1/b.sum(axis=1).A.ravel())
>>> # on older scipy versions the offsets parameter (default 0)
... # is a required argument, thus
... # c = sparse.diags(1/b.sum(axis=1).A.ravel(), 0)
...
>>> a/a.sum(axis=1, keepdims=True)
array([[ 0. , 0.9 , 0. , 0. , 0.1 , 0. ],
[ 0.125 , 0. , 0.3125 , 0. , 0. , 0.5625 ],
[ 0. , 1. , 0. , 0. , 0. , 0. ],
[ 1. , 0. , 0. , 0. , 0. , 0. ],
[ 0. , 0.375 , 0.20833333, 0.125 , 0. , 0.29166667],
[ 0.05555556, 0. , 0. , 0.44444444, 0.5 , 0. ]])
>>> (c @ b).todense() # on Python < 3.5 replace c @ b with c.dot(b)
matrix([[ 0. , 0.9 , 0. , 0. , 0.1 , 0. ],
[ 0.125 , 0. , 0.3125 , 0. , 0. , 0.5625 ],
[ 0. , 1. , 0. , 0. , 0. , 0. ],
[ 1. , 0. , 0. , 0. , 0. , 0. ],
[ 0. , 0.375 , 0.20833333, 0.125 , 0. , 0.29166667],
[ 0.05555556, 0. , 0. , 0.44444444, 0.5 , 0. ]])

关于python - scipy 稀疏矩阵除法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42225269/

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