Python 字典排序

Question

我有一个python字典

var = {'count': [1, 1, 1, 1, 1],
       'path': ['/media/anurag/Work/search_script/masterfile.txt',
                "/media/anurag/Work/search_script/Women's Running Shoes/Women's Running Shoes_2.csv",
                "/media/anurag/Work/search_script/Men's Running Shoes/masterfile.txt",
                "/media/anurag/Work/search_script/Men's Running Shoes/Men's Running Shoes_1.csv",
                "/media/anurag/Work/search_script/Men's Running Shoes/output.txt"],
       'modified': [1502974843.8277025, 1501594022.454686, 1501945289.3378062,
                    1501593976.6210368, 1501945143.4162745],
       'row': [9541, 8723, 1664, 506, 2200]}

现在我必须根据 modified 作为键进行排序。不扰乱秩序。为此，我使用了 pandas:

我的 Pandas 解决方案是

In [1]: import pandas as pd

In [2]: var = {'count': [1, 1, 1, 1, 1], 'path': ['/media/anurag/Work/search_script/masterfile.txt', "/media/anurag/Work/search_script/Women's Running Shoes/Women's Running Shoes_2.csv", "/media/anurag/Work/search_script/Men's Running Shoes/masterfile.txt", "/media/anurag/Work/search_script/Men's Running Shoes/Men's Running Shoes_1.csv", "/media/anurag/Work/search_script/Men's Running Shoes/output.txt"], 'modified': [1502974843.8277025, 1501594022.454686, 1501945289.3378062, 1501593976.6210368, 1501945143.4162745], 'row': [9541, 8723, 1664, 506, 2200]}

In [3]: search_result = pd.DataFrame.from_dict(var)

In [4]: search_result.sort_values('modified', inplace=True, ascending=False)

In [5]: search_result
Out[5]: 
   count      modified                                               path  \
0      1  1.502975e+09    /media/anurag/Work/search_script/masterfile.txt   
2      1  1.501945e+09  /media/anurag/Work/search_script/Men's Running...   
4      1  1.501945e+09  /media/anurag/Work/search_script/Men's Running...   
1      1  1.501594e+09  /media/anurag/Work/search_script/Women's Runni...   
3      1  1.501594e+09  /media/anurag/Work/search_script/Men's Running...   

    row  
0  9541  
2  1664  
4  2200  
1  8723  
3   506 

我可以不用 pandas 做这个吗？

Answer 1

您可以将对象存储为字典映射，然后使用适当的排序标准(由 key 指定)对此类对象的列表进行排序。像下面这样的东西-

var = {'count': [1, 1, 1, 1, 1], 'path': ['/media/anurag/Work/search_script/masterfile.txt', "/media/anurag/Work/search_script/Women's Running Shoes/Women's Running Shoes_2.csv", "/media/anurag/Work/search_script/Men's Running Shoes/masterfile.txt", "/media/anurag/Work/search_script/Men's Running Shoes/Men's Running Shoes_1.csv", "/media/anurag/Work/search_script/Men's Running Shoes/output.txt"], 'modified': [1502974843.8277025, 1501594022.454686, 1501945289.3378062, 1501593976.6210368, 1501945143.4162745], 'row': [9541, 8723, 1664, 506, 2200]}

objects = [{field: value[i] for field,value in var.items()}
           for i in range(len(var['count']))]

objects.sort(key=itemgetter('modified')) # you may add reverse=True as per need