python - 更清晰的代码来绕过在 Python 中打印 Int 值

Question

我有一段代码要求用户年龄。用户的输入是 int 类型。此外，如果用户不想输入任何内容，他们只需按“Enter”退出程序(如下):

print("What is your age?")
answer = int(input())
if answer == '':
    print("Don't want to disclose? That's fine.")

但是，当我按下 Enter 时，出现以下错误:

Traceback (most recent call last):
  File "C:/Users/test/PycharmProjects/exceptions/testinput.py", line 2, in <module>
    answer = int(input())
ValueError: invalid literal for int() with base 10: ''

Process finished with exit code 1

我知道我可以做一个 try block 并且代码像下面我想要的那样工作:

print("What is your age?")
try:
    answer = int(input())
    if answer == '':
        print()
except ValueError:
        print("Don't want to disclose? That's fine.")

我的问题是，除了 try block 之外，还有其他方法可以打印 int 类型的空白值吗？

Answer 1

当然:在转换为 int 之前检查输入:

answer = input("What is your age? ")
if answer == '':
    print("Don't want to disclose? That's fine.")
else:
    ...