python - 倒数

Question

我有一个这样组织的列表:

[('down', 0.0098000000000000309), 
('up', 0.0015000000000000568), 
('down', 0.008900000000000019), 
('down', 0.023300000000000098), 
('down', 0.011599999999999944), 
('down', 0.0027000000000000357), 
('up', 0.0023999999999999577), 
('up', 0.0065000000000000613), 
('down', 0.0057000000000000384), 
('down', 0.018400000000000083), 
('up', 0.009300000000000086), 
('down', 0.0038000000000000256), 
('down', 0.00050000000000005596), 
('up', 0.0082000000000000961), .....

“向后比较”的最佳方式是什么？ ，基本上我想返回"is"(或其他什么......)如果我们有一系列的 2 个“下降”然后是一个“上升”并且第二个值低于 0.0095。

我希望他说得有道理..

Answer 1

创建一个滑动窗口，并对其进行测试:

def slidingwindow(iterable):
    iterator = iter(iterable)
    first, second = iterator.next(), iterator.next()
    for next in iterator:
        yield (first, second, next)
        first, second = second, next

def testforcondition(data):
    for window in slidingwindow(data):
        direction = [w[0] for w in window]
        if direction == ['down', 'down', 'up'] and window[2][1] < 0.0095:
            return True
    return False