c++ - 如何创建变量数组 Arduino

Question

我将如何创建一个变量数组，例如.....

int incColor, c0, c1, c2, c3, c4, c5 = 0;
int circleArray[11][9] = { {c5, c5, c5, c5, c5, c5, c5, c5, c5}, 
                             {c4, c4, c4, c4, c4, c4, c4, c4, c4}, 
                             {c4, c3, c3, c3, c3, c3, c3, c3, c4}, 
                             {c4, c3, c2, c2, c2, c2, c2, c3, c4}, 
                             {c4, c3, c2, c1, c1, c1, c2, c3, c4}, 
                             {c4, c3, c2, c1, c0, c1, c2, c3, c4}, 
                             {c4, c3, c2, c1, c1, c1, c2, c3, c4}, 
                             {c4, c3, c2, c2, c2, c2, c2, c3, c4}, 
                             {c4, c3, c3, c3, c3, c3, c3, c3, c4}, 
                             {c4, c4, c4, c4, c4, c4, c4, c4, c4}, 
                             {c5, c5, c5, c5, c5, c5, c5, c5, c5} };

所以稍后在代码中我将能够像这样解决它们...

void circle(uint16_t mode) 
{
  switch (mode)
  {
     case 0:
     c0 = random(255);
     break; 
     case 1:
     c0 = incColor;
     incColor++;
     break;
  }
  for (int x = 0; x < 11; x++)
  {
     for (int y = 0; y < 9; y++)
    {
       strip.setPixelColor(x, y, Wheel(circleArray[x][y]));
    } 
  }
  c5 = c4;
  c4 = c3;
  c3 = c2;
  c2 = c1;
  c1 = c0;

}

上面的代码不起作用，我测试了 c5 和 circleArray[0][0]

c5 = 34
circleArray[0][0] = 0

circleArray[0][0] 应该与我认为的 c5 相同，但由于某种原因，该值未设置...

有人知道我在这里做错了什么吗？

~~~~~~~~~~~~~~编辑~~~~~~~~~~~~~~~~~

已修复!感谢@sj0h 帮助我找到了一个更简单的解决方案，所以现在我可以把它...

int c[6] = {0, 0, 0, 0, 0, 0};    
int  circleArray[11][9] = {  {5, 5, 5, 5, 5, 5, 5, 5, 5},
                             {4, 4, 4, 4, 4, 4, 4, 4, 4}, 
                             {4, 3, 3, 3, 3, 3, 3, 3, 4}, 
                             {4, 3, 2, 2, 2, 2, 2, 3, 4}, 
                             {4, 3, 2, 1, 1, 1, 2, 3, 4}, 
                             {4, 3, 2, 1, 0, 1, 2, 3, 4}, 
                             {4, 3, 2, 1, 1, 1, 2, 3, 4}, 
                             {4, 3, 2, 2, 2, 2, 2, 3, 4}, 
                             {4, 3, 3, 3, 3, 3, 3, 3, 4}, 
                             {4, 4, 4, 4, 4, 4, 4, 4, 4}, 
                             {5, 5, 5, 5, 5, 5, 5, 5, 5} };

void circle(uint16_t mode) 
{
  switch (mode)
  {
     case 0:
     c[0] = random(255);
     break; 
     case 1:
     c[0] = incColor;
     incColor++;
     break;
  }
  for (int x = 0; x < 11; x++)
  {
     for (int y = 0; y < 9; y++)
    {
       strip.setPixelColor(x, y, Wheel(c[circleArray[x][y]]));
    } 
  }
  c[5] = c[4];
  c[4] = c[3];
  c[3] = c[2];
  c[2] = c[1];
  c[1] = c[0];

}

进入现实生活中的应用....

Answer 1

引用可以做你想做的事:

int &circleArray[11][9] = ......

这将使 circleArray 成为引用数组而不是复制值。

---

编辑:标准不支持上述内容，支持取决于编译器。

改用指针，您将拥有

int *circleArray[11][9] = {{&c5, &c5, .....

然后将所有 circleArray 访问更改为 *circleArray[x][y] 而不是 circleArray[x][y]。

---

另一种可能更通用的方法是将颜色数组索引保留在 circleArray 中:

int incColor;
int cn[6] = {0,0,0,0,0,0};
int circleArray[11][9] = { {5,5,5,5,5,5,5,5,5},
                           {4,4 .....

然后 c0 将变为 c[0]，您将像这样访问数组值

cn[circleArray[x][y]]

您还可以制作 circleArray uint8_t 以节省一些空间，因为所有条目都将放在一个字节内。