c - 指针类型不兼容的警告

Question

我为散列函数编写了这个 block :

#include "debug.h"
#include "hash.h"

unsigned hash_add(unsigned char *name)
{
unsigned h;
for(h=0;*name;h+=name++);
return h;
}

我不断收到:

hashadd.c:7:17: warning: assignment makes integer from pointer without a cast [enabled  by default]

Answer 1

for``h+=name++ 的最后一个表达式是将地址(name 的类型为unsigned char *)分配给 h(unsigned int 类型)。改成

 for(h = 0; *name; h += *name++);  
                        ^Dereference the pointer before assigning to h.