java - 如何从输入文本中删除特殊字符

Question

我想从输入文本中删除所有特殊字符以及一些受限制的单词。

无论我想删除什么，它都会动态出现

(让我澄清一下:无论我需要排除哪些单词，它们都将动态提供 - 用户将决定需要排除哪些单词。这就是我没有包含正则表达式的原因。restricted_words_list(请参阅我的代码)将从数据库获取，只是为了检查我静态保存的代码是否正常工作)，

但出于演示目的，我将它们保存在字符串数组中，以确认我的代码是否正常工作。

public class TestKeyword {

    private static final String[] restricted_words_list={"@","of","an","^","#","<",">","(",")"};

    private static final Pattern restrictedReplacer;

    private static Set<String> restrictedWords = null;

    static {

        StringBuilder strb= new StringBuilder();

        for(String str:restricted_words_list){
            strb.append("\\b").append(Pattern.quote(str)).append("\\b|");
        }

        strb.setLength(strb.length()-1);
        restrictedReplacer = Pattern.compile(strb.toString(),Pattern.CASE_INSENSITIVE);

        strb = new StringBuilder();    
    }

    public static void main(String[] args)
    {
        String inputText = "abcd abc@ cbda ssef of jjj t#he g^g an wh&at ggg<g ss%ss ### (()) D^h^D";
        System.out.println("inputText : " + inputText);
        String modifiedText = restrictedWordCheck(inputText);
        System.out.println("Modified Text : " + modifiedText);

    }

    public static String restrictedWordCheck(String input){
        Matcher m = restrictedReplacer.matcher(input);
        StringBuffer strb = new StringBuffer(input.length());//ensuring capacity

        while(m.find()){
            if(restrictedWords==null)restrictedWords = new HashSet<String>();
            restrictedWords.add(m.group());  //m.group() returns what was matched
            m.appendReplacement(strb,""); //this writes out what came in between matching words

            for(int i=m.start();i<m.end();i++)
                strb.append("");
        }
        m.appendTail(strb);
        return strb.toString();
    }
}

输出是:

输入文本:abcd abc@ cbda ssef of jjj t#he g^g an wh&at ggg

修改文本:abcd abc@ cbda ssef jjj the gg wh&at gggg ss%ss ### (()) DhD

这里排除的单词是of和an，但只是一些特殊字符，而不是我在restricted_words_list中指定的所有字符

<小时/>

现在我有了更好的解决方案:

    String inputText = title;// assigning input 
    List<String> restricted_words_list = catalogueService.getWordStopper(); // getting all stopper words from database dynamically (inside getWordStopper() method just i wrote a query and getting list of words)
    String finalResult = "";
    List<String> stopperCleanText = new ArrayList<String>();

    String[] afterTextSplit = inputText.split("\\s"); // split and add to list

    for (int i = 0; i < afterTextSplit.length; i++) {
        stopperCleanText.add(afterTextSplit[i]); // adding to list
    }

    stopperCleanText.removeAll(restricted_words_list); // remove all word stopper 

    for (String addToString : stopperCleanText)
    {
        finalResult += addToString+";"; // add semicolon to cleaned text 
    }

    return finalResult;

Answer 1

public String replaceAll(String regex,
                         String replacement)

用给定的替换替换该字符串的每个子字符串(与给定的正则表达式匹配)。

参数:

• regex - 该字符串要成为的正则表达式匹配
• replacement - 每个匹配项要替换的字符串。

因此，您只需提供带有空字符串的替换参数即可。