给定一个项目列表 [音乐家] 和一个词典列表 [乐器] 如何以 pythonic 方式在它们之间建立关联?
因此,为了简化我的真实场景,请考虑以下内容:
musicians = [[700,"James","Hetfield", "jh@metallica.com","N/A"],
[701,"Lars","Ulrich","lu@metallica.com","N/A"],
[702,"Kirk","Hammett","kh@metallica.com","N/A"],
[703,"Robert","Trujillo", "rt@metallica.com","N/A"]]
instruments= ({700:"guitar"},{701:"drums"})
我的目标是用 instruments in instruments 替换 N/A is musicians。
下面的代码可以解决问题(但直觉来自 java/c++)
for m in musicians:
for i in instruments:
if m[0] in i:
m[4]=i[m[0]]
正确的预期结果是:
[[700, 'James', 'Hetfield', 'jh@metallica.com', 'guitar'], [701, 'Lars', 'Ulrich', 'lu@metallica.com', 'drums'], [702, 'Kirk', 'Hammett', 'kh@metallica.com', 'N/A'], [703, 'Robert', 'Trujillo', 'rt@metallica.com', 'N/A']]
问:python有经典的方法吗?
您可以使用 collections.ChainMap
组合您的乐器映射,然后使用列表理解:
from collections import ChainMap
cm = ChainMap(*instruments)
musicians = [[*x[:-1], cm.get(x[0], x[-1])] for x in musicians]
print(musicians)
# [[700, 'James', 'Hetfield', 'jh@metallica.com', 'guitar'],
# [701, 'Lars', 'Ulrich', 'lu@metallica.com', 'drums'],
# [702, 'Kirk', 'Hammett', 'kh@metallica.com', 'N/A'],
# [703, 'Robert', 'Trujillo', 'rt@metallica.com', 'N/A']]
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