Python获取多个逗号后面的字符串

Question

问题是我需要读取一个 text.txt 文件并从中获取非常具体的数据。该 text.txt 的条目如下所示

b(1,4,8,1,4,TEST,0,3,AAAA,Test,2-150,000)
a(1,1,3,1,3,BBBB,0,3,BBBB,Test,2-150,000)
a(1,0,2,1,4,TEST,0,3,CCCC,Test,2-150,000)
b(1,1,0,1,4,TEST,0,3,DDDD,Test,2-150,000)

所以现在我只需要那些带有“a(”的行，在那些行中我只需要在 5 和 8 逗号之后添加字符串，所以在第 2 行中它将是 BBBB ,BBBB

到目前为止我的代码是:

infile = open("text.txt","r") 
numlines = 0
found = []

for line in infile:
 numlines += 1
 if "a" in line:
  line=line[line.find("(")+1:line.find(")")]
  found.append(line.split(','))

wordLed=len(found)
for i in range(0,wordLed):
    print found[i]


infile.close()

这只是给了我在“，”处分隔的完整行，但我如何通过它们建立索引？

Answer 1

快速 短和脏:

with open('text.txt') as f:
    result = [line.split(',')[5:9:3] for line in f if line.startswith("a(")]
#                            ^^^^^^^
#                       "5 to 9 (excl.) by step of 3"
#                       that is items 5 and 5+3
#
#                       replace by [5] if you only want the fifths item
#                       replace by [5:9] if you want items from 5 to 9 (excl.) 

from pprint import pprint
pprint(result)

脏 因为缺少错误处理...

...无论如何，根据您的样本数据，这会产生:

[['BBBB', 'BBBB'], ['TEST', 'CCCC']]