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Python:返回列表不起作用

转载 作者:太空宇宙 更新时间:2023-11-04 07:08:38 25 4
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我正在尝试制作一个程序,可以在一个类(class)中添加/删除/显示学生,5 个类(class)是一个列表中的 5 个列表。

非常感谢您的帮助。

当我运行这段代码时:

global classes
def intro():
print("Welcome to Powerschool v2.0!")
print("Actions:")
print("1. Add Student")
print("2. Delete Student")
print("3. Show Students in a Class")
print("4. Show All Students")
x = int(input())
while x<1 or x>4:
print ("Please choose an action, 1-4.")
x = int(input())
if x == 1:
action1()
elif x == 2:
action2()
elif x == 3:
action3()
elif x == 4:
action4()
classes = [[],[],[],[],[]]
return classes
def action1():
print("Which Class? 1-5")
a = int(input())
print("Please enter the student's name.")
z = input()
classes[a-1].append(z)
again()
def action2():
print ("Which Class? 1-5")
print ("Which student?")
again()
def action3():
print ("Which Class? 1-5")
y = int(input())
if y == 1:
print (classes[0])
elif y == 2:
print (classes[1])
elif y == 3:
print (classes[2])
elif y == 4:
print (classes[3])
elif y == 5:
print (classes[4])
again()
def action4():
print (classes)
again()
def again():
print("Would you like to do something else? y/n")
h = input()
if h == "y":
intro()
else:
quit
def main():

intro()

main()

我的错误是:

Traceback (most recent call last):
File "C:\Documents and Settings\user1\My Documents\Downloads\az_studenttracker.py", line 67, in <module>
main()
File "C:\Documents and Settings\user1\My Documents\Downloads\az_studenttracker.py", line 65, in main
intro()
File "C:\Documents and Settings\user1\My Documents\Downloads\az_studenttracker.py", line 19, in intro
action1()
File "C:\Documents and Settings\user1\My Documents\Downloads\az_studenttracker.py", line 33, in action1
classes[a-1].append(z)
NameError: name 'classes' is not defined

我在 intro() 的末尾做了 return classes 但我发现这不起作用。我听从了一些建议,但实际上什么也没发生:/

最佳答案

您在 intro 方法中定义了 classes,即使它返回了它,您的 action1 方法也看不到任何任何地方名为 classes 的变量。

Relevant answer on Python scoperelevant documentation .

关于Python:返回列表不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26950574/

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