c - 从C上的简单链表中删除多个节点

Question

我想删除所有与键具有相同 idteam 的节点，但它会崩溃......我知道它也应该 free() 内存，但无论如何我认为这应该有效 :S

//defining the struct
struct players {
   int idplayer;
   int idteam;
   struct players *next;
 };

 struct players *first, *last;

//the function to delete the nodes
void delete(int key){
 struct players *post;
 struct players *pre;
 struct players *auxi;

 auxi = first; //initialization of auxi
 while(auxi != NULL) //this should run the loop till the end of the list?
 {
    if(auxi->idteam == key){ //condition to delete
        if(auxi == first) first = auxi->next; //erase for the case the node is the first one
        else pre->next = post; //erase in the case the node is anywhere else
      }
      pre = auxi; //saves the current value of auxi
      auxi = auxi->next; //increments the position of auxi
      post = auxi->next; //saves the position of the next element
     }
}

Answer 1

  auxi = auxi->next; //increments the position of auxi
  post = auxi->next; //saves the position of the next element

当 auxi 变为 NULL 时，您将最终执行 post = (NULL)->next;，这是访问冲突(崩溃)。

你真的不需要post，只需要:

if(auxi->idteam == key){ 
    if(auxi == first) first = auxi->next; 
    else pre->next = auxi->next; // We know auxi is not NULL, so this is safe.
  }