gpt4 book ai didi

c - 基于字符串比较的单词翻译程序——堆内存断言失败

转载 作者:太空宇宙 更新时间:2023-11-04 07:07:56 25 4
gpt4 key购买 nike

我制作了一个程序,它从文件 english_dictionary.txt 中读取 200 个最常用的英语单词,然后在 foreign_dictionary.txt 中我将这些单词的翻译放入相应的外语单词。

.txt 文件的内容放在两个 char * 类型的 200 元素数组中。

然后程序从文件 text_to_translate.txt 中读取,该文件包含英文文本,如果找到匹配项(这发生在compute_text 函数)。但它不起作用,我对堆内存断言失败,所以我想我用 malloc 或类似的东西出了问题,但我不明白我错在哪里。

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

void foreign_dictionary(char **foreign, FILE *fp){

char *buffer = malloc(30 * sizeof(char));
char *tok;
int i;

for (i = 0; i < 200; ++i){
fgets(buffer, 29, fp);
tok = strtok(buffer, "\n");
foreign[i] = malloc(strlen(tok) + 1);
strcpy(foreign[i], tok);
}

free(tok);
free(buffer);
}

void dictionary(char **english, FILE *fp){

int i;
char *tok;

char *buffer = malloc(30 * sizeof(char));

for (i = 0; i < 200; ++i){
fgets(buffer, 29, fp);
tok = strtok(buffer, " \n");
english[i] = malloc(strlen(tok) + 1);
strcpy(english[i], tok);
}
free(buffer);
free(tok);
}

void compute_text(char **text,FILE *fp){

char *buffer;
int i, j, flag = 0, words_number = 0, cnt_letters_word = 0;

buffer = malloc(100 * sizeof(char));

while (fgets(buffer, 100, fp) != NULL){
for (i = 0; i < 100; ++i){
if (buffer[i] == ' ' || buffer[i] == '\0'){
text[words_number] = malloc((cnt_letters_word + 1)* sizeof(char));
for (j = 0; j < cnt_letters_word; ++j){
if (isupper(buffer[flag + j]))
text[words_number][j] = tolower(buffer[flag + j]);
else
text[words_number][j] = buffer[flag + j];
}
text[words_number][cnt_letters_word] = '\0';
flag = i + 1;
cnt_letters_word = 0;
++words_number;
}
else if (buffer[i] == '\n' || buffer[i] == ',' || buffer[i] == '.' || buffer[i] == ';' || buffer[i] == ':')
;
else
++cnt_letters_word;
}
flag = 0;
cnt_letters_word = 0;
}
free(buffer);
}

int main(void){

char *foreign[200], *english[200], *text[50];

FILE *fp = fopen("foreign_dictionary.txt", "r");
foreign_dictionary(foreign, fp);
fclose(fp);
fp = fopen("english_dictionary.txt", "r");
dictionary(english, fp);
fclose(fp);
fp = fopen("text_to_translate.txt", "r");
compute_text(text, fp);
fclose(fp);

return 0;
}

最佳答案

在您的代码中,tok 没有指向动态分配的内存。你不需要(也不可能)free() 它。移除

 free(tok);

来自代码。

来自man page of free()

The free(ptr) function frees the memory space pointed to by ptr, which must have been returned by a previous call to malloc(), calloc() or realloc(). Otherwise, or if free(ptr) has already been called before, undefined behaviour. occurs.

就是说,在使用返回的指针之前,始终检查 fopen()malloc()(可能还有所有库函数)的返回值以确保成功。

关于c - 基于字符串比较的单词翻译程序——堆内存断言失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30884544/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com