python 3 : How do I sort both parallel lists?

Question

我需要能够按升序或降序对员工姓名及其年龄的平行列表进行排序。我可以得到一个列表进行排序，但我不知道如何得到第二个列表来分别将名字与他们的年龄配对。例如，我需要它看起来像这样。

Phil is 20 years old
Mike is 23 years old
Jenny is 38 years old
Jim is 65 years old

但它看起来像这样。

['Jim', 'Jenny', 'Phil', 'Mike'] is [20, 23, 38, 66] years old.

到目前为止，这是我的代码。

def get_name():
    employee_name = input("Enter the employee's name: ")
    return employee_name

def get_age():
    while True:
        try:
            employee_age = int(input("Enter the employee's age: "))
            return employee_age
        except ValueError:
            print("Please enter a valid number")

def main():
    num_age = []
    string_name = []

    print("This program sorts employee's by age.")

    while True:
        try:
            num_employees = int(input("Enter the number of employee's who are being evaluated: "))
            break
        except ValueError:
            print("Please enter a valid number.")

    while True:
        for i in range(num_employees):
            num_employees -= 1
            name = get_name()
            string_name += [name]

            age = get_age()
            num_age += [age]

        if num_employees == 0:
            print(str(sorted(string_name)) + " is " + (str(sorted(num_age))) + " years old.")
            break

main()

Answer 1

解决此问题的一种经典方法是使用 Python 的内置 zip 函数将列表连接在一起，然后对数据进行排序。排序完成后，您可以返回到原始(但已排序)列表:

list1 = ['Jim', 'Jenny', 'Phil', 'Mike']
list2 = [65, 38, 20, 23]
list2, list1 = (list(t) for t in zip(*sorted(zip(list2, list1))))