c - 如何打印从函数返回的数组元素作为指针？

Question

我想打印月份名称，它是一个数组元素(作为指针从函数返回..)

这是我的功能:

/*I have taken this from book by Dennis Ritchie*/
/* month name : return name of n-th month */
char *month_name(int n){
     static char *name[] = {
     "illegal month","January","February","March","April","May","June","July",
     "August","September","October","November","December"};
return (n < 1 || n > 12) ? name[0] : name[n];
}

现在我无法在我的 main() 函数中收集这个指针。我试过这种方式

void main(void)
{
 int k = 0, i = 0;
 char *s;
 printf("Enter month number\n");
 scanf("%d",&k);

 s = month_name(k);
 for(i = 0; *(s+i) != '/0'; i++)
      printf("%c",*(s+i));
 getch();
}

Answer 1

之所以不行，是因为下面写的不对

for ( i = 0; *(s+i) != '/0'; i++)

你在现实中试图实现的是在空终止符处停止。然而!您代码中的空终止符不正确。

请更改为以下内容:

for ( i = 0; *(s+i) != '\0'; i++)

Null terminator = '\0'. You wrote '/0'.