java - 如何在spring中设置sessionAttributes并在不同的jsps和 Controller 中访问它们

Question

我是 spring&java 的初学者。如何正确地将 UserDetailedInfo 模型传递到 SessionAttrtibutes 中以在不同的 Controller 和不同的 jsps 中访问它？我正在尝试使用 spring 框架创建一个登录系统。

//this is my mainpagecontroller.java
@Controller
@SessionAttributes("model")
public class MainPageController{   

    @RequestMapping(value="/signin", method=RequestMethod.POST)
    @ResponseBody
    public Map<String, Object>  userSignIn(@RequestParam Map<String,String>  param, ModelMap sessions) throws UnsupportedEncodingException {
        FormHelpers helper = new FormHelpers();
         Map<String, Object> resp = new HashMap<String, Object>();
        resp.put("status", helper.signIn(param).getError());
        sessions.addAttribute("model",resp);

        System.out.println(resp);
        //System.out.println(info.get);
        return resp;
    }
}   

//formhelpers.java
public UserDetailedInfo signIn(Map<String, String> data) {
      Map<String, String> params = new HashMap<String, String>();

      SigninModel model = new SigninModel();
      model.setEmail(data.get("email"));
      model.setPassword(data.get("password"));
      params.put("email", model.getEmail());
      params.put("password", model.getPassword());
    try {
        ObjectMapper mapper = new ObjectMapper();
        String response = GlobalHelper.callService(RestServicesUrl.SIGNIN_URL, params);
        UserDetailedInfo info =  mapper.readValue(response, UserDetailedInfo.class);
        System.out.println("error"+info.getError());
        return info;
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        return new UserDetailedInfo();
    }
}

//singedinhomepagecontroller.java
@Controller
@RequestMapping(value="/main")
@SessionAttributes("model")
public class SignedInHomePageController
{
    @RequestMapping(method=RequestMethod.GET)
    @ResponseBody
    public ModelAndView displaySignInHomePage(@ModelAttribute FormHelpers model)
    {   
        ModelAndView view = new ModelAndView("homepage");
        System.out.println(model.signIn().getEmail()); //unable to access the from session
        return view;
     }

}

//home.jsp

Answer 1

在参数上使用http session 并设置属性和获取属性方法

public ModelAndView test(HttpSession session) 
{
      session.setAttribute("success" , "successfully accessed");
}

然后在其他 Controller 方法中

public ModelAndView test(HttpSession session) 
{
      String sessionVar = session.getAttribute("success");
}

关于创建登录系统我建议使用http://projects.spring.io/spring-security/