java - 使用 JAXB2 解码 XML 返回空列表 (Scala)

Question

我正在使用 JAXB2 将 XML 字符串解码到名为 AccountInfo 的 java 对象中。 AccountInfo 包含一个 accountID 和一个 Location 对象列表。目前，我可以从 xml 中提取 acountID，但我的位置列表始终为空。任何帮助将不胜感激!谢谢!

这是我尝试解码的 xml:

<AccountInfo AccountID="640480">
  <Location LocationID="1490075"/>
  <Location LocationID="8900561"/>
  <Location LocationID="2367782"/>
  <Location LocationID="2226598"/>
</AccountInfo>

<小时/>

我的 AccountInfo 架构(自动生成我的 java 对象):

<schema xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.cspire.com/omnia/schema" xmlns:tns="http://www.cspire.com/omnia/schema"
elementFormDefault="qualified">

<xsd:element name="AccountInfo">
  <xsd:complexType>
    <xsd:sequence>
      <xsd:element name="Location" type="tns:Location" minOccurs="0" maxOccurs="unbounded" />
    </xsd:sequence>
    <xsd:attribute name="AccountID" type="xsd:string"></xsd:attribute>
  </xsd:complexType>
</xsd:element>

<xsd:complexType name="Location">
  <xsd:attribute name="LocationID" type="xsd:string" />
</xsd:complexType>

</schema>

<小时/>

(部分)AccountInfo.java

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {"location"})
@XmlRootElement(name = "AccountInfo")
public class AccountInfo implements Equals, HashCode, ToString
{

  @XmlElement(name = "Location")
  protected List<Location> location;
  @XmlAttribute(name = "AccountID")
  protected String accountID;

  public AccountInfo() {
    super();
  }

  public AccountInfo(final List<Location> location, final String accountID) {
    this.location = location;
    this.accountID = accountID;
  }

  public List<Location> getLocation() {
    if (location == null) {
        location = new ArrayList<Location>();
    }
    return this.location;
  }

  public String getAccountID() {
    return accountID;
  }

  public void setAccountID(String value) {
    this.accountID = value;
  }

<小时/>

(部分)Location.java

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "Location")
public class Location implements Equals, HashCode, ToString
{
  @XmlAttribute(name = "LocationID")
  protected String locationID;

  public Location() {
    super();
  }

  public Location(final String locationID) {
    this.locationID = locationID;
  }

  public String getLocationID() {
    return locationID;
  }

  public void setLocationID(String value) {
    this.locationID = value;
  }

<小时/>

我的主要目标:

object Main extends App {
  val xml = <string xmlns="http://schemas.martin-group.com/openomnia">&lt;AccountInfo AccountID="640480"&gt;&lt;Location LocationID="1490075"/&gt;&lt;Location LocationID="8900561"/&gt;&lt;Location LocationID="2367782"/&gt;&lt;Location LocationID="2226598"/&gt;&lt;/AccountInfo&gt;</string>
  val testXML = xml \\ "string" text

  val jc = JAXBContext.newInstance(classOf[AccountInfo])
  val unmarshaller = jc.createUnmarshaller
  val result = unmarshaller.unmarshal(new StreamSource(new StringReader(testXML), classOf[AccountInfo]).getValue

  println(result)
  println("Account ID: " + result.getAccountID)
  println(result.getLocation.isEmpty)
}

<小时/>

结果:

com.cspire.omnia.schema.AccountInfo@74c3d5ab[location=<null>, accountID=640480]
Account ID: 640480
true

Answer 1

尝试解码的文档与您的 XML 架构不匹配。

<AccountInfo AccountID="640480">
  <Location LocationID="1490075"/>
  <Location LocationID="8900561"/>
  <Location LocationID="2367782"/>
  <Location LocationID="2226598"/>
</AccountInfo>

要使其与 XML 架构(请参阅 targetNamespace 和 elementFormDefault 属性)和 JAXB 映射(请参阅 package-info 类上的 @XmlSchema 注释)匹配，您需要声明命名空间信息。

<AccountInfo xmlns="http://www.cspire.com/omnia/schema" AccountID="640480">
  <Location LocationID="1490075"/>
  <Location LocationID="8900561"/>
  <Location LocationID="2367782"/>
  <Location LocationID="2226598"/>
</AccountInfo>

<小时/>

调试提示

当您无法让 JAXB 解编 XML 文档时，请尝试填充对象模型并编码它以查看 JAXB 期望的 XML 文档。