Java JFrame 设置最大位置

Question

提前抱歉，我不太知道这叫什么。

我正在尝试设置我的 JFrame，以便当它穿过屏幕宽度(或高度)时，它会停止移动。这是我到目前为止的代码...

public void moverMouseDragged(java.awt.event.MouseEvent evt) {
        int x = evt.getXOnScreen()-xMouse;
        int y = evt.getYOnScreen()-yMouse;
        Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
        int width2 = (int) screenSize.getWidth();
        int height2 = (int) screenSize.getHeight();
        if(this.getX()<0){x=0;}
        if(this.getY()<0){y=0;}
        if((this.getX()+width)>width2){x=width2;}
        if((this.getY()+height)>height2){y=height2;}
        this.setLocation(x, y);
        System.out.println(this.getY()+"\n"+this.getX());
    }
    public void moverMousePressed(java.awt.event.MouseEvent evt) {                                   
        xMouse = evt.getX();
        yMouse = evt.getY();
    }

这只适用于屏幕的顶部和左侧。它充满了小故障，老实说我不知道​​该去哪里。

Answer 1

我修好了:

public void moverMouseDragged(java.awt.event.MouseEvent evt) {
        int x = evt.getXOnScreen()-xMouse;
        int y = evt.getYOnScreen()-yMouse;

        Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
        int xScreen = (int) screenSize.getWidth();
        int yScreen = (int) screenSize.getHeight();
        //System.out.println(width+" "+height);

        if(x<0){x=0;}
        if(y<0){y=0;}
        if(y>(yScreen-height)){y=yScreen-height;}
        if(x>(xScreen-width)){x=xScreen-width;}

        this.setLocation(x, y);
        //System.out.println(this.getY()+"\n"+this.getX());
    }
    public void moverMousePressed(java.awt.event.MouseEvent evt) {                                   
        xMouse = evt.getX();
        yMouse = evt.getY();
    }

准确地完成它应该做的事情:阻止 JFrame 越过屏幕的任意 4 个边。