python - 陷入无限循环

Question

我正在尝试用 Python 编写一个程序，将十进制数转换为等效的十六进制数。当我运行该程序时，它为我提供了正确的转换，但它在无限循环中运行。我不确定无限循环到底发生在哪里。这是我的代码:

def remainderToHex(remainder):
    if remainder <= 9:
        remainder = str (remainder)
    elif remainder == 10:
        remainder = "A"
    elif remainder == 11:
        remainder = "B"
    elif remainder == 12:
        remainder = "C"
    elif remainder == 13:
        remainder = "D"
    elif remainder == 14:
        remainder = "E"
    elif remainder == 15:
        remainder = "F"
    return remainder

def decToHex(decNum):
    hexNum = ""
    quotient = decNum
    divNum=16
    if quotient == 0:
        hexNum = 0
    while quotient > 0:
        remainder = quotient % divNum
        convertedHex= remainderToHex(remainder)
        quotient = int (quotient / divNum)
        hexNum = convertedHex + hexNum 
    return hexNum

def main():
    decNum=int(raw_input("Please enter a non negative number OR enter -1 to quit: "))
    while decNum >= -1:
        hexNumber = decToHex(decNum)
        print decNum, "convered to hex is: ", hexNumber
    print "Thank you" 

谢谢!

Answer 1

您正在执行 while decNum >= -1。假设用户没有立即输入 -1，那么 decNum 将永远变得小于 -1，while 循环将永远不会结束。相反，使用 if 语句。如果用户输入 -1，则结束该过程，否则进行转换。

正如已经指出的那样，>= 应该是 >