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python - 无法使用 SOAPpy 调用 Web 服务方法

转载 作者:太空宇宙 更新时间:2023-11-04 06:58:11 25 4
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我正在尝试使用 SOAPpy 调用网络服务:

from SOAPpy import SOAPProxy

url = 'http://www.webservicex.net/WeatherForecast.asmx'

server = SOAPProxy(url);
print server.GetWeatherByPlaceName('Dallas');
print server.GetWeatherByZipCode ('33126');

服务器调用失败:

Traceback (most recent call last):
File "soap_test.py", line 6, in <module>
print server.GetWeatherByPlaceName('Dallas');
File "C:\usr\bin\Python26\lib\site-packages\SOAPpy\Client.py", line 451, in __call__
return self.__r_call(*args, **kw)
File "C:\usr\bin\Python26\lib\site-packages\SOAPpy\Client.py", line 473, in __r_call
self.__hd, self.__ma)
File "C:\usr\bin\Python26\lib\site-packages\SOAPpy\Client.py", line 387, in __call
raise p
SOAPpy.Types.faultType: <Fault soap:Client: System.Web.Services.Protocols.SoapException: Server did not recognize the value of HTTP Header SOAPAction: GetWeatherByPlaceName.
at System.Web.Services.Protocols.Soap11ServerProtocolHelper.RouteRequest()
at System.Web.Services.Protocols.SoapServerProtocol.RouteRequest(SoapServerMessage message)
at System.Web.Services.Protocols.SoapServerProtocol.Initialize()
at System.Web.Services.Protocols.ServerProtocol.SetContext(Type type, HttpContext context, HttpRequest request, HttpResponse response)
at System.Web.Services.Protocols.ServerProtocolFactory.Create(Type type, HttpContext context, HttpRequest request, HttpResponse response, Boolean& abortProcessing): >

我做错了什么?

最佳答案

使用 .NET 网络服务时,您可以向调用添加 soap 操作覆盖。像下面这样。确认工作代码。

import SOAPpy

ns = 'http://www.webservicex.net'
url = '%s/WeatherForecast.asmx' % ns

server = SOAPpy.SOAPProxy( url, namespace=ns )
#following is required for .NET
server.config.buildWithNamespacePrefix = 0
#adding the soapaction is required for .NET
print server._sa( '%s/GetWeatherByPlaceName' %ns ).GetWeatherByPlaceName( PlaceName='Dallas' )
print server._sa( '%s/GetWeatherByZipCode' %ns ).GetWeatherByZipCode( ZipCode='33126' )

有人写了一个class做类似的事情。

上述 .Net 包装器的修改版本:

import SOAPpy

class SOAPProxy( SOAPpy.SOAPProxy ):
"""Wrapper class for SOAPpy.SOAPProxy

Designed so it will prepend the namespace to the action in the
SOAPAction HTTP headers.
"""

def __call( self, name, args, kw, ns=None, sa=None, hd=None, ma=None ):
sa = sa or self.soapaction
ns = ns or self.namespace
self.config.buildWithNamespacePrefix = 0

# Only prepend namespace if no soapaction was given.
if ns and not sa:
if ns.endswith( '/' ):
sa = '%s%s' % ( ns , name )
else:
sa = '%s/%s' % ( ns , name )

#fixup boolean args - .net wants lowercase
for arg in kw:
if isinstance( kw[ arg ], types.BooleanType ):
kw[ arg ] = SOAPpy.Types.booleanType( kw[ arg ] )


return SOAPpy.SOAPProxy.__call( self, name, args, kw, ns, sa, hd, ma )

if __name__ == '__main__':
print __doc__

关于python - 无法使用 SOAPpy 调用 Web 服务方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1768185/

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